In the system shown in Figure 1, the transformers are connected star-star with both star points grounded and the generator is connected in star with its star points grounded. The per unit impedances of each element on a 40 MVA base are given in Table 1 and the voltage levels are given in Table 2. Z [p.u.] 0 2 jöj Generator 0.01 +j0.08 p.u. L Figure 1: A section of the distribution system Transformer T1 Line V BASE [KV] 0.04 + j 0.03 + j 0.15000000000000002 0.06000000000000000 Generator Table 1: Sequence impedances (p.u. on 40 MVA base) 3 T2 181. Line 3 10 Table 2: Voltage bases (kV) Load 1 Transformer T2 Load Current A load current of 11.316 kA is flowing with a lagging power factor of 90 %. Convert this to a current vector in per-unit. IL = 0.04 + j 0.06000000000000000

In the system shown in Figure 1, the transformers are connected star-star with both star points grounded and the generator is connected in star with its star points grounded. The per unit impedances of each element on a 40 MVA base are given in Table 1 and the voltage levels are given in Table 2. Z [p.u.] 0 2 jöj Generator 0.01 +j0.08 p.u. L Figure 1: A section of the distribution system Transformer T1 Line V BASE [KV] 0.04 + j 0.03 + j 0.15000000000000002 0.06000000000000000 Generator Table 1: Sequence impedances (p.u. on 40 MVA base) 3 T2 181. Line 3 10 Table 2: Voltage bases (kV) Load 1 Transformer T2 Load Current A load current of 11.316 kA is flowing with a lagging power factor of 90 %. Convert this to a current vector in per-unit. IL = 0.04 + j 0.06000000000000000

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Related questions

Q: 6. Transformers have the capability to step up or step down AC voltage True False

Q: Ql-phase step down transformer 1250 KVA, 110002200 V, 50 Hz. The resistance iphase and leakage…

Q: A three-phase, 230 V, 72 kVA, 0.9 pf (lagging) load is supplied by three 29 kVA, 1330/230 V, 60 Hz…

A: Given, The single line diagram is shown below, Where,Feeder impedance, ZF=0.003+j0.015 Ω/phaseLine…

Q: Determine the ratio of the kW output of transformer A to the kW output of transformer B. Both…

Q: Please, I do not want a theoretical solution or using artificial intelligence. I want a solution on…

Q: QUESTION 12 A single phase 600v/120v transformer has a load of 30 ohms resistive and 20 ohms…

Q: Two three-phase transformers of equal voltage ratios are operating in parallel. The load draws a…

A: Given: load current IL=200∠-cos-10.9IL=200∠-25.84° AZ1=0.1+j0.3 ΩZ2=0.2+j0.5 Ω

Q: Ql-phase step down transformer 1250 KVA, 1 1000/2200 V, 50 Hz .The resistance /phase and leakage…

Concept explainers

Three-Phase Transformers

Three-segment transformers are a type of transformer used to transform voltages of electrical systems into three ranges. Two type transformers are shell-type transformer and core type transformer. In brief, it could be described because of the exquisite kinds of configurations.

Transformer

Ever since electricity has been created, people have started using it in its entirety. We see many types of Transformers in the neighborhoods. Some are smaller in size and some are very large. They are used according to their requirements. Many of us have seen the electrical transformer but they do not know what work they are engaged in.

Question

In the system shown in Figure 1, the transformers are connected star-star with both star points grounded and the generator is connected in
star with its star points grounded. The per unit impedances of each element on a 40 MVA base are given in Table 1 and the voltage levels are
given in Table 2.
Z [p.u.]
0
2
tööt
Generator
0.01 +j0.08
p.u.
L
Figure 1: A section of the distribution system
Transformer T1
Line
V BASE [KV]
0.04 + j
0.03 + j
0.15000000000000002 0.06000000000000000
Generator
Table 1: Sequence impedances (p.u. on 40 MVA base)
3
T2
181.
Line
3
10
Table 2: Voltage bases (kV)
Load
1
Transformer T2
Load Current
A load current of 11.316 kA is flowing with a lagging power factor of 90 %. Convert this to a current vector in per-unit.
IL =
0.04 + j
0.06000000000000000

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1: Introduction

VIEW

Step 2: Calculation

VIEW

Solution

VIEW

Step by step

Solved in 3 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.

Similar questions

Two single phase transformers A and B with equal turns ratio have reactance of j3.2 and j19.2 referred to secondary. When operated in parallel, the load sharing of 100 kW at 0.8 pf lag between A and B transformers would respectively be a) 75 kw and 25kw b) 60 kw and 40 kw c) 20 kw and 80 kw d) 25 kw and 75 kw
3. A non-ideal 1-phase transformer has turns ratio 5:1 with 120Vac primary. The primary impedance is 1 + j1 Ohms, and the secondary impedance is 0.2 + j0.2 Ohms. Assume the core impedance (R0 and X0) can be neglected. A resistive load of 12 Ohms is connected to the secondary. What is the primary current magnitude? What is the secondary voltage magnitude? What is the efficiency of this transformer with this load?
1. A single-phase power system as shown in Figure 1 consists of a 240 V, 60 Hz generator supplying a load, Zod = 8 + j6 Q through a transmission line of impedance, Zne = 0.08 + j0.14 Q. Answer the following questions: (1) transformer, T; and T2. Determine the voltage at the load and transmission line losses without the (ii) Determine the voltage at the load and transmission line losses with the transformer, T, and T2. T1 T2 1:10 10:1 IG Zaine Zioad source Figure 1
What do the connection angles and groups show in transformers? For example, where are the Yy0 , Dy5 ,Yd5, Yz5 group transformers used?
If the line-to-line primary voltage and line current is 1.0 at 0 degrees, what is the secondary line- to-line voltage for the following three-phase transformers? Assume a turns ratio of N = 10. Express answer in polar form. a. Delta-to-Delta: b. Delta-to-Wye: c. Wye-to-Delta: d. Wye-to-Wye:
Ql-phase step down transformer 1250 KVA, 10002200 V, 50 Hz The resistance /phase and leakage reactanceiphase of the primary winding are 0.78 2 and 4.82 and the corresponding values for the secondary winding are 0.012 and 0.002 respectively if the primary winding is connected in delta and secondary in star calculate: )The voltage to be applied at normal frequency to the primary to circulate full-load through it when the secondary is short-circuited li) The full load copper loss
A 10 MVA three phase load is to be served by a three phase transformer at aline voltage of 13.8 kV. The supply side voltage(line-line) is 138 kV. Varioussingle phase transformers are available in the warehouse but all havewindings with voltage ratings under 100 kV and current ratings under 250 A.Is it possible to serve the load using only three single phase transformers? Ifso, specify the three phase connections and the low and high voltage ratingsof the single phase transformers.
If the load draws a current of 2727 A, in phase, from a generator, which of the following statement is true? O A. The reactive power is flowing from generator to the load and the real power is flowing from the load to the generator. O B. Since the current is in phase with the generator voltage, both the real and reactive power is flowing from the generator to the load. O .Since the current is leading the generator, both the real and reactive power is flowing from the load to the generator. O D. The real power is flowing from generator to the load and the reactive power is flowing from the load to the generator. O E. None of the other choices are correct