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Draw the final compound C produced in the following synthetic scheme. Pay attention to stereochemistry for this problem. Draw the molecule on the canvas by choosing buttons from the Tools (for bonds and charges), Atoms, and Templates toolbars. HOCH,CH,OH (1 equiv) CH;CH,MgBr B H;0* C H+ > View Available Hint(s) H OH Br A O O O D O Submit Previous Answers X Incorrect; Try Again; 3 attempts remaining

Draw the final compound C produced in the following synthetic scheme. Pay attention to stereochemistry for this problem. Draw the molecule on the canvas by choosing buttons from the Tools (for bonds and charges), Atoms, and Templates toolbars. HOCH,CH,OH (1 equiv) CH;CH,MgBr B H;0* C H+ > View Available Hint(s) H OH Br A O O O D O Submit Previous Answers X Incorrect; Try Again; 3 attempts remaining

Biochemistry
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
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Can you assist me in identifying what it is I am doing wrong? Are my stereocenters correct? Thank you so much.

Original Question:

Draw the final compound C produced in the following synthetic scheme. Pay attention to stereochemistry for this problem.

 

**Part C** **Instructions:** Draw the final compound C produced in the following synthetic scheme. Pay attention to stereochemistry for this problem. **Task:** Draw the molecule on the canvas by choosing buttons from the Tools (for bonds and charges), Atoms, and Templates toolbars. **Synthetic Scheme:** 1. The initial reactant is a ketone with a side chain. 2. Step 1: The reactant is treated with ethylene glycol (\(HOCH_2CH_2OH\)) in the presence of acid (\(H^+\)) to form compound A. 3. Step 2: Compound A is reacted with ethylmagnesium bromide (\(CH_3CH_2MgBr\)) to form compound B. 4. Step 3: Compound B is treated with acidic water (\(H_3O^+\)) to produce the final compound C. **Molecular Drawing Attempt:** - A cyclohexane ring with an ethyl group and hydroxyl group substituents is drawn. - Stereochemistry is indicated: - The ethyl group is shown in a bold wedge indicating it is coming out of the plane. - The hydroxyl group is shown in a dashed wedge indicating it is going into the plane. **Feedback:** - The attempt is marked as incorrect with 3 attempts remaining. **Hints:** Use tools like highlighting available atoms (H, C, N, O) and choosing proper bond angles to accurately depict stereochemistry while drawing structures.
Transcribed Image Text:**Part C** **Instructions:** Draw the final compound C produced in the following synthetic scheme. Pay attention to stereochemistry for this problem. **Task:** Draw the molecule on the canvas by choosing buttons from the Tools (for bonds and charges), Atoms, and Templates toolbars. **Synthetic Scheme:** 1. The initial reactant is a ketone with a side chain. 2. Step 1: The reactant is treated with ethylene glycol (\(HOCH_2CH_2OH\)) in the presence of acid (\(H^+\)) to form compound A. 3. Step 2: Compound A is reacted with ethylmagnesium bromide (\(CH_3CH_2MgBr\)) to form compound B. 4. Step 3: Compound B is treated with acidic water (\(H_3O^+\)) to produce the final compound C. **Molecular Drawing Attempt:** - A cyclohexane ring with an ethyl group and hydroxyl group substituents is drawn. - Stereochemistry is indicated: - The ethyl group is shown in a bold wedge indicating it is coming out of the plane. - The hydroxyl group is shown in a dashed wedge indicating it is going into the plane. **Feedback:** - The attempt is marked as incorrect with 3 attempts remaining. **Hints:** Use tools like highlighting available atoms (H, C, N, O) and choosing proper bond angles to accurately depict stereochemistry while drawing structures.
The image depicts the chemical structure of a molecule, which is a representation of the arrangement of atoms within the compound. ### Description: - **Carbon Backbone**: The structure primarily consists of a chain of carbon atoms connected by single bonds, with one branch off the main chain. - **Functional Groups**: - **Hydroxyl Group (OH)**: A hydroxyl group is attached to one of the carbon atoms in the chain, indicated by the "OH" label in red. This group is positioned on a wedge, showing that it is oriented above the plane of the main carbon chain. - **Carbonyl Group (C=O)**: A carbonyl group is present, identified by a double bond between a carbon and an oxygen atom. This group is also highlighted in red. - **Stereochemistry**: The use of solid and dashed wedges signifies the three-dimensional orientation of the bonds: - **Solid Wedge**: Represents bonds coming out of the plane towards the viewer. - **Dashed Wedge**: Represents bonds going behind the plane away from the viewer. This molecular structure is a representation often used in organic chemistry to convey information about the spatial arrangement of atoms, which is crucial for understanding the molecule's reactivity and interactions.
Transcribed Image Text:The image depicts the chemical structure of a molecule, which is a representation of the arrangement of atoms within the compound. ### Description: - **Carbon Backbone**: The structure primarily consists of a chain of carbon atoms connected by single bonds, with one branch off the main chain. - **Functional Groups**: - **Hydroxyl Group (OH)**: A hydroxyl group is attached to one of the carbon atoms in the chain, indicated by the "OH" label in red. This group is positioned on a wedge, showing that it is oriented above the plane of the main carbon chain. - **Carbonyl Group (C=O)**: A carbonyl group is present, identified by a double bond between a carbon and an oxygen atom. This group is also highlighted in red. - **Stereochemistry**: The use of solid and dashed wedges signifies the three-dimensional orientation of the bonds: - **Solid Wedge**: Represents bonds coming out of the plane towards the viewer. - **Dashed Wedge**: Represents bonds going behind the plane away from the viewer. This molecular structure is a representation often used in organic chemistry to convey information about the spatial arrangement of atoms, which is crucial for understanding the molecule's reactivity and interactions.
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