Draw a triacylglycerol (triglyceride) made from glycerol, myristic acid [CH3(CH2) 12COOH], palmitic acid [CH3(CH2)14 COOH], and oleic acid [CH3(CH2),CH=CH(CH2),COOH(cis)]. Place palmitic acid at the middle position. Cis/trans isometry is graded; it may help to draw hydrogen atoms associated with the carbon atoms of the double bond. Select Draw Templates More Erase C H о
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- Draw a triacylglycerol (triglyceride) made from glycerol, myristic acid [CH₂(CH₂)2COOH], palmitic acid [CH₂(CH₂)₁4COOH], and oleic acid [CH₂(CH₂)₂CH=CH(CH₂),COOH(cis)] . Place palmitic acid at the middle position. Cis/trans isometry is graded; it may help to draw hydrogen atoms associated with the carbon atoms of the double bond. Incorrect What did I do wrong?Which of the statements are true? Unsaturated fats have higher melting points than saturated fats. Fats that contain more saturated fatty acid residues than unsaturated fatty acid residues are more likely to be solid at room temperature. Triacylglycerols (triglycerides) are carboxylic acids. Unsaturated fats are more likely than saturated fats to be liquid at room temperature. Triacylglycerols (triglycerides) contain ester bonds.Arrange the fatty acids from highest melting point to lowest melting point. - CH3(CH2)10COOH - CH3(CH2)7CH=CH(CH2)7COOH - CH3(CH2)4(CH=CHCH2)4(CH2)2COOH - CH3(CH2)14COOH Select the statements about fatty acid melting points that are true. - A saturated fatty acid with a greater molar mass has a higher melting point than a saturated fatty acid with a lower molar mass. - A saturated fatty acid with a greater molar mass has a lower melting point than a saturated fatty acid with a lower molar mass. - A saturated fatty acid has a higher melting point than an unsaturated fatty acid. - A saturated fatty acid has a lower melting point than an unsaturated fatty acid.
- Classify each of the molecules in the table. molecule CH3 CH₂-CH=CH-CH₂-CH=CH-(CH₂)9 CH3-(CH₂) 10 i - OH CH3–CH2–CH=CH−(CH2)5 -OH O=O C-OH type of molecule (check all that apply) fatty acid monoglyceride diglyceride triglyceride saturated unsaturated monounsaturated polyunsaturated omega-3 omega-6 fatty acid monoglyceride diglyceride triglyceride saturated unsaturated monounsaturated polyunsaturated omega-3 omega-6 fatty acid monoglyceride diglyceride triglyceride saturated unsaturated monounsaturated polyunsaturated omega-3 omega-6Using condensed structural formulas and showing all products with any catalysts, draw the remainder of the equation for the hydrogenation of the following triacylglycerol.Please explain each
- Can u help me? Was this correct answer is first fatty acid is five carbon (CH2)5 alkene nine carbon (CH2) 9, second fatty acid is one carbon (CH2)1 alkene six carbon (CH2)6 alkene five carbon (CH2)5, third fatty acid is sixteen carbon (CH2)16?Classify each of the molecules in the table. molecule CH3CH₂CH=CH-CH₂-CH=CH (CH₂)6 O || C-OH CH3 CH₂-CH=CH-CH₂-CH=CH-(CH₂)4 —CH=CH—(CH₂)3 - CH3 - (CH₂)5 C-OH C-OH type of molecule (check all that apply) fatty acid monoglyceride diglyceride triglyceride saturated unsaturated monounsaturated polyunsaturated w-3 w-6 fatty acid monoglyceride diglyceride triglyceride saturated unsaturated monounsaturated polyunsaturated w-3 w-6 fatty acid monoglyceride diglyceride triglyceride saturated unsaturated monounsaturated polyunsaturated w-3 w-6The main fatty acid component of the triacylglycerols in coconut oil is lauric acid, CH3(CH2)10COOH. Explain why coconut oil is a liquid at room temperature even though it contains a large fraction of this saturated fatty acid.
- 4. The ester you drew in Question #1 has a melting point range of 32 - 35 °C. The methyl ester of mono-unsaturated palmitoleic acid (IUPAC name: hexadec-9-enoic acid) has a considerably lower melting point range: -0.5-+0.5 °C. a) Explain what it means for a fatty acid to be "mono-unsaturated." b) Illustrate your explanation by drawing the structure of the methyl ester of octadec-11-enoic acid. (Be sure to draw the geometric stereoisomer that is commonly found in nature.)Triglycerides can be classified by the number of double bonds present in the hydrocarbon chain. Categorize this triglyceride based on the degree of saturation 04-0-8-compon C-(CH₂)-CH₂ CH-0-C-(CH₂CH=CH-CH=CH-CH₂ O=U C46-0-8 -10M) CH, CH= CH₂-0-C H=CH-CH=CH-CH=CH-CH₂ O Polysaturated Saturated Monounsaturated O Polyunsaturated2. Identify whether the following fatty acids are saturated or unsaturated. a. CH3(CH2)sCH=CH(CH2)7COOH b. CH3(CH2)7CH=CH(CH2)7COOH c. CH3(CH2)10COOH d. CH3(CH2)16COOH e. CH;CH2(CH=CHCH2)3(CH2)6COOH 3. Explain the importance of lipid content in the structure of biological membranes