Question 18 (1 point) You have prepared a solution of NaOH by diluting a stock 1.5 M NaOH solution with approximately 200 mL of water. You now need to determine its precise concentration and you have performed five titration trials to standardize your solution. Here are the results of your trials: trial # mass of potassium biphthalate (mg) volume of NaOH solution (mL) 12.30 mL 1 180 mg 15.20 mL 2 180 mg 12.20 mL 3 180 mg 13.90 mL 4 180 mg 12.50 mL 5 180 mg You now have to calculate the average molar concentration of your NaOH solution and you want it to be as precise as possible. How are you going to do it? I will only use trials 1 and 3 I will use all the trials for my calculations I will discard trial 4 I will discard trials 2 and 4

Chemistry: An Atoms First Approach
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Author:Steven S. Zumdahl, Susan A. Zumdahl
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Chapter6: Types Of Chemical Reactions And Solution Stoichiometry
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Problem 80E: The concentration of a certain sodium hydroxide solution was determined by using the solution to...
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Question 18 (1 point)
You have prepared a solution of NaOH by diluting a stock 1.5 M NaOH solution with
approximately 200 mL of water. You now need to determine its precise concentration
and you have performed five titration trials to standardize your solution. Here are
the results of your trials:
trial #
mass of potassium biphthalate (mg)
volume of NaOH solution (mL)
12.30 mL
1
180 mg
15.20 mL
2
180 mg
12.20 mL
3
180 mg
13.90 mL
4
180 mg
12.50 mL
5
180 mg
You now have to calculate the average molar concentration of your NaOH solution
and you want it to be as precise as possible. How are you going to do it?
I will only use trials 1 and 3
I will use all the trials for my calculations
I will discard trial 4
I will discard trials 2 and 4
Transcribed Image Text:Question 18 (1 point) You have prepared a solution of NaOH by diluting a stock 1.5 M NaOH solution with approximately 200 mL of water. You now need to determine its precise concentration and you have performed five titration trials to standardize your solution. Here are the results of your trials: trial # mass of potassium biphthalate (mg) volume of NaOH solution (mL) 12.30 mL 1 180 mg 15.20 mL 2 180 mg 12.20 mL 3 180 mg 13.90 mL 4 180 mg 12.50 mL 5 180 mg You now have to calculate the average molar concentration of your NaOH solution and you want it to be as precise as possible. How are you going to do it? I will only use trials 1 and 3 I will use all the trials for my calculations I will discard trial 4 I will discard trials 2 and 4
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