Determine the reaction order for Na2S2O3 using calculations described in the background section. Show your work. Note that your answer will probably not be a whole number as it is in the examples. Data Table 2: Varying Concentrations of Na2S203Well #C4, D4Well #C5, D5Well #C6, D6# of Drops of 888.HCI# of Drops of6.8H20# of Drops of1264Na,S203Concentration1.01.01.0(M) ofHCI StockSolutionConcentration 0.300.300.30| (M) ofNazS,03Stock SolutionReaction0.40.40.4Concentration(М) of HCIafter Mixing inWellReaction0.180.090.06Concentration(M) ofNazS203 afterMixing in WellTrial 125Reaction Time3723(sec)Trial 222Reaction Time4128(sec)Average23.53925.5Reaction Time(sec)Reaction0.0260.0150.024"Rate" (sec-)

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Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Determine the reaction order for Na₂S₂O₃ using calculations described in the background section. Show your work. Note that your answer will probably not be a whole number as it is in the examples.

Data Table 2: Varying Concentrations of Na2S203
Well #C4, D4
Well #C5, D5
Well #C6, D6
# of Drops of 8
8
8.
HCI
# of Drops of
6.
8
H20
# of Drops of
12
6
4
Na,S203
Concentration
1.0
1.0
1.0
(M) of
HCI Stock
Solution
Concentration 0.30
0.30
0.30
| (M) of
NazS,03
Stock Solution
Reaction
0.4
0.4
0.4
Concentration
(М) of HCI
after Mixing in
Well
Reaction
0.18
0.09
0.06
Concentration
(M) of
NazS203 after
Mixing in Well
Trial 1
25
Reaction Time
37
23
(sec)
Trial 2
22
Reaction Time
41
28
(sec)
Average
23.5
39
25.5
Reaction Time
(sec)
Reaction
0.026
0.015
0.024
"Rate" (sec-)

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