In python please Determine if a triangle formed by three points a(x1,y1), b(x2, y2), andc(x3, y3) is non-degenerate. If two given points, p = (xp, yp) and q = (xq,yq), are located on or inde a triangle, they belong to the triangle.Return the correct scenario number.Scenarios:⚫0. the lines do not form a valid non-degenerate triangle1: point p belongs to the triangle but point q does not2: point q belongs to the triangle but point p does not• 3: both points p and q belong to the triangle• 4: neither point p nor point q belong to the triangleNote: A triangle is considered non-degenerate if it meets the followingconditions, where |ab| denotes the length of the line segmentbetween points a and b:A|ab|+|bc|>|ac||bc|+|ac|ab|lab+lac>|bc|

To solve this problem in Python, we can break it down into several steps: Check if the points form a…

Answered: Determine if a triangle formed by three…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Find out what value the Bresenham's circle drawing decision parameter p should have. Here, a set of detailed instructions for Bresenham's method for drawing a circle is provided.
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Find the value of the Bresenham's circle drawing method's decision parameter p. Step-by-step instructions are given for how Bresenham's method for making a circle works.
Determine the appropriate value for the decision parameter p to use in the Bresenham's circle drawing procedure. The instructions that Bresenham developed for drawing a circle are presented in this article in the form of an algorithm that may be followed step by step.
A robot is initially located at position (0, 0) in a grid [−5, 5] × [−5, 5]. The robot can move randomly in any of the directions: up, down, left, right. The robot can only move one step at a time. For each move, print the direction of the move and the current position of the robot. If the robot makes a circle, which means it moves back to the original place, print “Back to the origin!” to the console and stop the program. If it reaches the boundary of the grid, print “Hit the boundary!” to the console and stop the program. A successful run of your code may look like: Down (0,-1) Down (0,-2) Up (0,-1) Left (-1,-1) Left (-2,-1) Up (-2,0) Left (-3,0) Left (-4,0) Left (-5,0) Hit the boundary! or Left (-1,0) Down (-1,-1) Right (0,-1) Up (0,0) Back to the origin! Instructions: This program is to give you practice using the control flow, the random number generator, and output formatting. You may not use stdafx.h. Include header comments. Include <iomanip> to format your output. Name…
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QUESTION 15 Select all valid forms of "breadcrumbs". Choose all that apply. A string of individual light bulbs leading towards a door Enemies placed individually down a narrow winding path Multiple individual floor mats placed next to each other, in a line, that curves to the right Individual gold coins spinning in the air, placed in a line that angles up towards a flag pole
Input Output Explanation 4 11 There are 4 test cases without round 1+2*3+4 1000000006 brackets. 1*2-3 123 • Case 1: It is straightforward to evaluate that 1+2 x 3 +4 = 123 invalid +-* 11. • Case 2:1 x 2 – 3 = -1. In modular arithmetic, -1 is 1 000 000 006 (mod 1 000 000 007). • Case 3: By definition E → integer. Therefore 123 evaluates to 123. • Case 4: Each operator must have operands. This expression is invalid. 4 9 There are 4 test cases with round (1+2)*3 invalid brackets. () invalid () 100 (((1))) • Case 1: It is straightforward to evaluate that (1+ 2) × 3 = 9. • Case 2: Empty brackets are not 1 allowed by definition. • Case 3: Not only empty brackets are disallowed, but also there misses an operator between () and 100. • Case 4: By definition E (E). Therefore E → (E) → ((E)) → (((E))) → (((1))), which evaluates to 1.
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You are asked to determine the value of the decision parameter p used in Bresenham's circle drawing algorithm. The algorithm for drawing circles by Bresenham is presented in a series of instructions.
1. In each iteration of a loop, generate a random number, and use it to determine some attribute of what is drawn in that iteration. For example, draw one shape multiple times in random locations and/or at random sizes OR 2. write a triply nested for loop to add even more complexity to your drawing than with a doubly nested loop

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