Convert the following C code snippet into the corresponding x86 assembly instructions. 1) if(x<=0) { z = 0; } else if(x <= 10000) { z = 1; } else { z = 2; }
Convert the following C code snippet into the corresponding x86 assembly instructions. 1) if(x<=0) { z = 0; } else if(x <= 10000) { z = 1; } else { z = 2; }
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
Convert the following C code snippet into the corresponding x86 assembly instructions.
1)
if(x<=0)
{
z = 0;
}
else if(x <= 10000)
{
z = 1;
}
else
{
z = 2;
}
2)
int n = 5;
for(int i = 0; i <= 10; i++)
{
cout<<n<<” x ”<<i<<” = ”<<n*i<<endl;
}
3)
int number = 10;
int result = 1;
while (number <= 15)
{
result = result * number;
number++;
}
cout<<"Resulted Value : "<<result;
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