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An instruction pipeline consists of following 5 stages: IF = Instruction Fetch, ID = Instruction Decode, EX = Execute, MA = Memory Access and WB = Register Write Back. Consider the following code: 1. LOAD R. [1000] Ry 4(R,) Ry R. R3 Ry Rq. R, R Ry, R3 R = Memory [1000] R = Memory [R,+ 4] R = R, x Rg R, = R, + R, R, = R4- R, %3D 2. LOAD %3D 3. MUL 4. DIV 5. SUB Assume that each stage takes 1 clock cycle for all the instructions. The number of cycles saved to execute the code, by using operand forwarding over a without operand forwarding is

An instruction pipeline consists of following 5 stages: IF = Instruction Fetch, ID = Instruction Decode, EX = Execute, MA = Memory Access and WB = Register Write Back. Consider the following code: 1. LOAD R. [1000] Ry 4(R,) Ry R. R3 Ry Rq. R, R Ry, R3 R = Memory [1000] R = Memory [R,+ 4] R = R, x Rg R, = R, + R, R, = R4- R, %3D 2. LOAD %3D 3. MUL 4. DIV 5. SUB Assume that each stage takes 1 clock cycle for all the instructions. The number of cycles saved to execute the code, by using operand forwarding over a without operand forwarding is

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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An instruction pipeline consists of following 5 stages: IF = Instruction Fetch, ID = Instruction Decode, EX = Execute, MA = Memory Access and WB = Register Write Back. Consider the following code: 1. LOAD 2. LOAD R, [1000] Ry 4(R,) Ry Ry. R3 Ry R, R. R, Ry R3 R = Memory [1000] R3 = Memory [R, + 4] R = R, x R3 R3 = R, + R, R = R4- R3 %3D 3. MUL 4. DIV 5. SUB Assume that each stage takes 1 clock cycle for all the instructions. The number of cycles saved to execute the code, by using operand forwarding over a without operand forwarding is
Transcribed Image Text:An instruction pipeline consists of following 5 stages: IF = Instruction Fetch, ID = Instruction Decode, EX = Execute, MA = Memory Access and WB = Register Write Back. Consider the following code: 1. LOAD 2. LOAD R, [1000] Ry 4(R,) Ry Ry. R3 Ry R, R. R, Ry R3 R = Memory [1000] R3 = Memory [R, + 4] R = R, x R3 R3 = R, + R, R = R4- R3 %3D 3. MUL 4. DIV 5. SUB Assume that each stage takes 1 clock cycle for all the instructions. The number of cycles saved to execute the code, by using operand forwarding over a without operand forwarding is
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