3. Translate the following C code to MIPS assembly code. Try to use a minimum number of instructions. Register allocations - i $s0 - j $s1 - base of A[] $s2 - base of B[] $s3 3.1. if (i == j) i += 2; else j--; j += i; 3.2. A[j] = B[i+1] + B[3]; 3.3. (10 points) i = 0; while (j != A[i]) { i++; }
3. Translate the following C code to MIPS assembly code. Try to use a minimum number of instructions. Register allocations - i $s0 - j $s1 - base of A[] $s2 - base of B[] $s3 3.1. if (i == j) i += 2; else j--; j += i; 3.2. A[j] = B[i+1] + B[3]; 3.3. (10 points) i = 0; while (j != A[i]) { i++; }
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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3. Translate the following C code to MIPS assembly code. Try to use a minimum number of instructions.
Register allocations
- i $s0
- j $s1
- base of A[] $s2
- base of B[] $s3
3.1.
if (i == j)
i += 2;
else
j--;
j += i;
3.2.
A[j] = B[i+1] + B[3];
3.3. (10 points)
i = 0;
while (j != A[i]) {
i++;
}
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