An instruction pipeline consists of following 5 stages: IF = Instruction Fetch, ID = Instruction Decode, EX = Execute, MA = Memory Access and WB = Register Write Back. Consider the following code: 1. LOAD R, [1000] Ry 4(R,) Ry R, Rg Ry Rq, R, R, Ry R3 R = Memory [1000] R = Memory [R, + 4] R = R, x Rg R, = R, + R, R, = R, - R3 2. LOAD %3D 3. MUL 4. DIV 5. SUB Assume that each stage takes 1 clock cycle for all the instructions. The number of cycles saved to execute the code, by using operand forwarding over a without operand forwarding is

Computer Networking: A Top-Down Approach (7th Edition)
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An instruction pipeline consists of following 5 stages:
IF = Instruction Fetch, ID = Instruction Decode, EX = Execute,
MA = Memory Access and WB = Register Write Back.
%3D
Consider the following code:
1. LOAD
R. [1000]
Ry 4(R,)
Ry R. R3
Ry Rq. R.
Rg Ry R3
Rq = Memory [1000]
R3 = Memory [R,+ 4]
R = R, x R3
R3 = R, + R4
R, = R4 – R3
2. LOAD
%3D
3. MUL
%3D
4. DIV
%3D
5. SUB
Assume that each stage takes 1 clock cycle for all the instructions. The number of cycles saved to execute the code, by using operand
forwarding over a without operand forwarding is
Transcribed Image Text:An instruction pipeline consists of following 5 stages: IF = Instruction Fetch, ID = Instruction Decode, EX = Execute, MA = Memory Access and WB = Register Write Back. %3D Consider the following code: 1. LOAD R. [1000] Ry 4(R,) Ry R. R3 Ry Rq. R. Rg Ry R3 Rq = Memory [1000] R3 = Memory [R,+ 4] R = R, x R3 R3 = R, + R4 R, = R4 – R3 2. LOAD %3D 3. MUL %3D 4. DIV %3D 5. SUB Assume that each stage takes 1 clock cycle for all the instructions. The number of cycles saved to execute the code, by using operand forwarding over a without operand forwarding is
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