Consider this reaction: 2SO₂(g) → 2SO₂(g) + O₂(g) At a certain temperature it obeys this rate law. = (0.00295 S-¹) [SO3] rate= Suppose a vessel contains SO3 at a concentration of 1.28M. Calculate the concentration of SO3 reaction is important. Round your answer to 2 significant digits. in the vessel 270. seconds later. You may assume no other

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Chapter1: Chemical Foundations
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**Reaction Rate Calculation Example**

Consider the following reaction:

\[ 2SO_3(g) \rightarrow 2SO_2(g) + O_2(g) \]

At a certain temperature, this reaction follows the rate law given by:

\[ \text{rate} = (0.00295 \, \text{s}^{-1}) [SO_3] \]

Suppose a vessel contains \( SO_3 \) at an initial concentration of \( 1.28 \, M \). Calculate the concentration of \( SO_3 \) in the vessel after 270 seconds. You may assume no other reaction is important.

**Steps to Calculate:**

1. Initial concentration of \( SO_3 \): \( [SO_3]_0 = 1.28 \, M \)
2. Rate constant: \( k = 0.00295 \, \text{s}^{-1} \)
3. Time: \( t = 270 \, \text{seconds} \)

Since this is a first-order reaction in \( SO_3 \), we use the first-order integrated rate law:

\[ [SO_3]_t = [SO_3]_0 \cdot e^{-kt} \]

Substitute the values into the equation:

\[ [SO_3]_{270} = 1.28 \, M \cdot e^{-(0.00295 \, \text{s}^{-1} \cdot 270 \, \text{s})} \]

4. Calculate the exponent:

\[ -(0.00295 \, \text{s}^{-1} \cdot 270 \, \text{s}) = -0.7965 \]

5. Calculate the exponential term:

\[ e^{-0.7965} \approx 0.451 \]

6. Calculate the concentration of \( SO_3 \) after 270 seconds:

\[ [SO_3]_{270} = 1.28 \, M \cdot 0.451 \approx 0.577 \, M \]

Round your answer to 2 significant digits:

\[ [SO_3]_{270} \approx 0.58 \, M \]

**Final Answer:** The concentration of \( SO_3 \) after 270 seconds is approximately \( 0.58 \, M \).

**Diagram Explanation:**

- There is a box for entering the calculated concentration of
Transcribed Image Text:**Reaction Rate Calculation Example** Consider the following reaction: \[ 2SO_3(g) \rightarrow 2SO_2(g) + O_2(g) \] At a certain temperature, this reaction follows the rate law given by: \[ \text{rate} = (0.00295 \, \text{s}^{-1}) [SO_3] \] Suppose a vessel contains \( SO_3 \) at an initial concentration of \( 1.28 \, M \). Calculate the concentration of \( SO_3 \) in the vessel after 270 seconds. You may assume no other reaction is important. **Steps to Calculate:** 1. Initial concentration of \( SO_3 \): \( [SO_3]_0 = 1.28 \, M \) 2. Rate constant: \( k = 0.00295 \, \text{s}^{-1} \) 3. Time: \( t = 270 \, \text{seconds} \) Since this is a first-order reaction in \( SO_3 \), we use the first-order integrated rate law: \[ [SO_3]_t = [SO_3]_0 \cdot e^{-kt} \] Substitute the values into the equation: \[ [SO_3]_{270} = 1.28 \, M \cdot e^{-(0.00295 \, \text{s}^{-1} \cdot 270 \, \text{s})} \] 4. Calculate the exponent: \[ -(0.00295 \, \text{s}^{-1} \cdot 270 \, \text{s}) = -0.7965 \] 5. Calculate the exponential term: \[ e^{-0.7965} \approx 0.451 \] 6. Calculate the concentration of \( SO_3 \) after 270 seconds: \[ [SO_3]_{270} = 1.28 \, M \cdot 0.451 \approx 0.577 \, M \] Round your answer to 2 significant digits: \[ [SO_3]_{270} \approx 0.58 \, M \] **Final Answer:** The concentration of \( SO_3 \) after 270 seconds is approximately \( 0.58 \, M \). **Diagram Explanation:** - There is a box for entering the calculated concentration of
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