Suppose the decomposition of ozone proceeds by the following mechanism: step elementary reaction rate constant 10₂(g) → 0₂(g) +0 (g) k₁ 2 03 (g) +0 (g) 20₂ (8) k₂ Suppose also k₁ <
Suppose the decomposition of ozone proceeds by the following mechanism: step elementary reaction rate constant 10₂(g) → 0₂(g) +0 (g) k₁ 2 03 (g) +0 (g) 20₂ (8) k₂ Suppose also k₁ <
Chemistry
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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◇ KINETICS AND EQUILIBRIUM
Writing the rate law implied by a simple mechanism with an initi...
Suppose the decomposition of ozone proceeds by the following mechanism:
step elementary reaction rate constant
10₂(g) → 0₂ (g) +0 (g)
k₁
2 03 (g) +0 (g) → 20₂ (g)
k₂
Suppose also k₁ <<k₂. That is, the first step is much slower than the second.
Write the balanced chemical
equation for the overall
chemical reaction.
Write the experimentally-
observable rate law for the
overall chemical reaction.
Note: your answer should not
contain the concentrations of
any intermediates.
rate = k
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Expert Solution

Step 1: Law of mass action
Answer:
Law of mass action states that rate of reaction is directly proportional to the molar concentration of the reactant species present in the rate determining step. Slowest step of the reaction is the rate determining step.
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