At a certain temperature the rate of this reaction is first order in SO₂ with a rate constant of 0.0213 s 2SO3 (g) →2SO₂(g) + O₂ (g) Suppose a vessel contains SO3 at a concentration of 1.27 M. Calculate how long it takes for the concentration of SO3 to decrease by 87.0%. You may assume no other reaction is important. Round your answer to 2 significant digits. A 0.9 X 3

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At a certain temperature, the rate of this reaction is first order in \( \text{SO}_3 \) with a rate constant of \( 0.0213 \, \text{s}^{-1} \):

\[ 2\text{SO}_3(g) \rightarrow 2\text{SO}_2(g) + \text{O}_2(g) \]

Suppose a vessel contains \( \text{SO}_3 \) at a concentration of \( 1.27 \, M \). Calculate how long it takes for the concentration of \( \text{SO}_3 \) to decrease by \( 87.0\% \). You may assume no other reaction is important.

Round your answer to 2 significant digits.

\[
\begin{array}{|c|}
\hline
\text{s} \\
\hline
\end{array}
\]

---
- The text describes a chemical reaction involving sulfur trioxide (\( \text{SO}_3 \)). 
- It specifies the reaction is first-order and provides the rate constant.
- The problem asks to calculate the time needed for a specific concentration decrease.
Transcribed Image Text:At a certain temperature, the rate of this reaction is first order in \( \text{SO}_3 \) with a rate constant of \( 0.0213 \, \text{s}^{-1} \): \[ 2\text{SO}_3(g) \rightarrow 2\text{SO}_2(g) + \text{O}_2(g) \] Suppose a vessel contains \( \text{SO}_3 \) at a concentration of \( 1.27 \, M \). Calculate how long it takes for the concentration of \( \text{SO}_3 \) to decrease by \( 87.0\% \). You may assume no other reaction is important. Round your answer to 2 significant digits. \[ \begin{array}{|c|} \hline \text{s} \\ \hline \end{array} \] --- - The text describes a chemical reaction involving sulfur trioxide (\( \text{SO}_3 \)). - It specifies the reaction is first-order and provides the rate constant. - The problem asks to calculate the time needed for a specific concentration decrease.
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Step 1: Integrated rate law for first order reaction

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