A + 2B C + 2D →>> The reaction is known to be first order in [A] and second order in [B]. When 0.30 moles A and 0.30 moles of B are placed in a 1.00 L container at 25 °C, 1.8 x 10-4 moles of C are formed per second with no change in volume. What is the rate constant at 25 °C? k = [?] Do not include units in your answer. Magnitude of k Enter
A + 2B C + 2D →>> The reaction is known to be first order in [A] and second order in [B]. When 0.30 moles A and 0.30 moles of B are placed in a 1.00 L container at 25 °C, 1.8 x 10-4 moles of C are formed per second with no change in volume. What is the rate constant at 25 °C? k = [?] Do not include units in your answer. Magnitude of k Enter
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
100%
![### Reaction Rate Calculation
**Reaction:**
\[ A + 2B \rightarrow C + 2D \]
**Given:**
- The reaction is first order in [A] and second order in [B].
- Initial concentrations: 0.30 moles of A and 0.30 moles of B.
- Volume of container: 1.00 L.
- Temperature: 25 °C.
- Rate of formation of C: \( 1.8 \times 10^{-4} \) moles per second.
**Task:**
Determine the rate constant, \( k \), at 25 °C.
### Calculation:
1. **Determine the Concentrations:**
- \([A] = \frac{0.30 \text{ moles}}{1.00 \text{ L}} = 0.30 \text{ M}\)
- \([B] = \frac{0.30 \text{ moles}}{1.00 \text{ L}} = 0.30 \text{ M}\)
2. **Rate Law:**
Since the reaction is first order in [A] and second order in [B], the rate law can be expressed as:
\[ \text{Rate} = k [A][B]^2 \]
3. **Plug in the Given Values:**
- Rate: \( 1.8 \times 10^{-4} \) M/s
- \([A] = 0.30 \text{ M}\)
- \([B] = 0.30 \text{ M}\)
\[ 1.8 \times 10^{-4} = k (0.30)(0.30)^2 \]
4. **Solve for \( k \):**
\[ k = \frac{1.8 \times 10^{-4}}{(0.30)(0.09)} \]
\[ k = \frac{1.8 \times 10^{-4}}{0.027} \]
\[ k = 6.67 \times 10^{-3} \]
### Answer:
- Enter the magnitude of \( k \): **\[ 6.67 \times 10^{-3} \]**
Please ensure not to include units in the answer text box. The rate constant, \( k \), is calculated based on the provided reaction conditions at 25 °C.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc6e1cbf0-df3a-4970-a570-9594e2279a44%2F0b5d6a18-f392-4456-acf8-a9b86415ff53%2Fh408iv8c_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Reaction Rate Calculation
**Reaction:**
\[ A + 2B \rightarrow C + 2D \]
**Given:**
- The reaction is first order in [A] and second order in [B].
- Initial concentrations: 0.30 moles of A and 0.30 moles of B.
- Volume of container: 1.00 L.
- Temperature: 25 °C.
- Rate of formation of C: \( 1.8 \times 10^{-4} \) moles per second.
**Task:**
Determine the rate constant, \( k \), at 25 °C.
### Calculation:
1. **Determine the Concentrations:**
- \([A] = \frac{0.30 \text{ moles}}{1.00 \text{ L}} = 0.30 \text{ M}\)
- \([B] = \frac{0.30 \text{ moles}}{1.00 \text{ L}} = 0.30 \text{ M}\)
2. **Rate Law:**
Since the reaction is first order in [A] and second order in [B], the rate law can be expressed as:
\[ \text{Rate} = k [A][B]^2 \]
3. **Plug in the Given Values:**
- Rate: \( 1.8 \times 10^{-4} \) M/s
- \([A] = 0.30 \text{ M}\)
- \([B] = 0.30 \text{ M}\)
\[ 1.8 \times 10^{-4} = k (0.30)(0.30)^2 \]
4. **Solve for \( k \):**
\[ k = \frac{1.8 \times 10^{-4}}{(0.30)(0.09)} \]
\[ k = \frac{1.8 \times 10^{-4}}{0.027} \]
\[ k = 6.67 \times 10^{-3} \]
### Answer:
- Enter the magnitude of \( k \): **\[ 6.67 \times 10^{-3} \]**
Please ensure not to include units in the answer text box. The rate constant, \( k \), is calculated based on the provided reaction conditions at 25 °C.
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images

Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Recommended textbooks for you

Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning

Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education

Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning

Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning

Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education

Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning

Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education

Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning

Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY