Consider this reaction: 2H₂PO4 (aq) → P₂O, (aq) + 3H₂O (aq) - At a certain temperature it obeys this rate law. rate = (0.048 M¹.s¹) [H₂PO₂] S Suppose a vessel contains H₂PO at a concentration of 1.06 M. Calculate how long it takes for the concentration of H₂PO to decrease to 0.053 M. You may assume no other reaction is important. Round your answer to 2 significant digits. ☐x10

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### Chemical Kinetics: Reaction Rate Problem

Consider the following reaction:

\[ 2H_3PO_4(aq) \rightarrow P_2O_5(aq) + 3H_2O(aq) \]

At a certain temperature, it follows this rate law:

\[ \text{rate} = (0.048 \, \text{M}^{-1} \cdot \text{s}^{-1}) [H_3PO_4]^2 \]

#### Problem Statement:

Suppose a vessel contains \( H_3PO_4 \) at an initial concentration of \( 1.06 \, \text{M} \). Calculate the time required for the concentration of \( H_3PO_4 \) to decrease to \( 0.053 \, \text{M} \), assuming no other reactions are significant.

Please round your answer to two significant digits.

#### Input Box:

- **Answer box placeholder:** _s (seconds)

---
#### Explanation of Calculation:

To solve for the required time (\( t \)), we need to integrate the rate law for a second-order reaction, which is in the form:

\[ \frac{1}{[A]_t} = \frac{1}{[A]_0} + kt \]

where:
- \([A]_t\) is the concentration of \( H_3PO_4 \) at time \( t \)
- \([A]_0\) is the initial concentration of \( H_3PO_4 \)
- \( k \) is the rate constant
- \( t \) is time

Given data:
- \([H_3PO_4]_0 = 1.06 \, \text{M}\)
- \([H_3PO_4]_t = 0.053 \, \text{M}\)
- \( k = 0.048 \, \text{M}^{-1} \cdot \text{s}^{-1} \)

By substituting the given concentrations and rate constant into the integrated rate law, we can solve for \( t \).
Transcribed Image Text:### Chemical Kinetics: Reaction Rate Problem Consider the following reaction: \[ 2H_3PO_4(aq) \rightarrow P_2O_5(aq) + 3H_2O(aq) \] At a certain temperature, it follows this rate law: \[ \text{rate} = (0.048 \, \text{M}^{-1} \cdot \text{s}^{-1}) [H_3PO_4]^2 \] #### Problem Statement: Suppose a vessel contains \( H_3PO_4 \) at an initial concentration of \( 1.06 \, \text{M} \). Calculate the time required for the concentration of \( H_3PO_4 \) to decrease to \( 0.053 \, \text{M} \), assuming no other reactions are significant. Please round your answer to two significant digits. #### Input Box: - **Answer box placeholder:** _s (seconds) --- #### Explanation of Calculation: To solve for the required time (\( t \)), we need to integrate the rate law for a second-order reaction, which is in the form: \[ \frac{1}{[A]_t} = \frac{1}{[A]_0} + kt \] where: - \([A]_t\) is the concentration of \( H_3PO_4 \) at time \( t \) - \([A]_0\) is the initial concentration of \( H_3PO_4 \) - \( k \) is the rate constant - \( t \) is time Given data: - \([H_3PO_4]_0 = 1.06 \, \text{M}\) - \([H_3PO_4]_t = 0.053 \, \text{M}\) - \( k = 0.048 \, \text{M}^{-1} \cdot \text{s}^{-1} \) By substituting the given concentrations and rate constant into the integrated rate law, we can solve for \( t \).
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