One mechanism for the destruction of ozone in the upper atmosphere is Os (9) + NO(g) → NO₂(g) + O2(g) Slow NO₂(g) + 0(g) → NO(g) + O₂(g) Fast Overall reaction O3(g) + O(g) → 20₂ (g) a. Which species is a catalyst? ONO 003 002 O NO2 b. Which species is an intermediate? ONO 003 002 O NO₂ c. E₂ for the uncatalyzed reaction 03 (g) + 0(g) → 20₂ (g) is 14.0 kj. E for the same reaction when catalyzed is 11.9 kJ. What is the ratio of the rate constant for the catalyzed reaction to that for the uncatalyzed reaction at 85°C? Assume the frequency factor A is the same for each reaction. Ratio = [References) Submit Answer Try Another Version frem atempt remaning (Pr Previous
One mechanism for the destruction of ozone in the upper atmosphere is Os (9) + NO(g) → NO₂(g) + O2(g) Slow NO₂(g) + 0(g) → NO(g) + O₂(g) Fast Overall reaction O3(g) + O(g) → 20₂ (g) a. Which species is a catalyst? ONO 003 002 O NO2 b. Which species is an intermediate? ONO 003 002 O NO₂ c. E₂ for the uncatalyzed reaction 03 (g) + 0(g) → 20₂ (g) is 14.0 kj. E for the same reaction when catalyzed is 11.9 kJ. What is the ratio of the rate constant for the catalyzed reaction to that for the uncatalyzed reaction at 85°C? Assume the frequency factor A is the same for each reaction. Ratio = [References) Submit Answer Try Another Version frem atempt remaning (Pr Previous
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:One mechanism for the destruction of ozone in the upper atmosphere is
Os (9) + NO(g) → NO₂(g) + O2(g) Slow
NO₂(g) + 0(g) → NO(g) + O₂(g) Fast
Overall reaction O3(g) + O(g) → 20₂ (g)
a. Which species is a catalyst?
ONO
003
002
O NO2
b. Which species is an intermediate?
ONO
003
002
O NO₂
c. E₂ for the uncatalyzed reaction
03 (g) + 0(g) → 20₂ (g)
is 14.0 kj. E for the same reaction when catalyzed is 11.9 kJ. What is the ratio of the rate constant for the catalyzed reaction to that
for the uncatalyzed reaction at 85°C? Assume the frequency factor A is the same for each reaction.
Ratio =
[References)
Submit Answer
Try Another Version
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