The reaction C,H;(g) → 2 C,H, (g) has an activation energy of 262 kJ/mol. At 600.0 K, the rate constant, k, is 6.1 × 10-8 s-1. What is the value of the rate constant at 750.0 K? k = 1.34 х103 s-1 Incorrect
The reaction C,H;(g) → 2 C,H, (g) has an activation energy of 262 kJ/mol. At 600.0 K, the rate constant, k, is 6.1 × 10-8 s-1. What is the value of the rate constant at 750.0 K? k = 1.34 х103 s-1 Incorrect
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### General Chemistry 4th Edition
### McQuarrie • Rock • Gallogly
### University Science Books presented by Macmillan Learning
---
### Reaction Analysis
The reaction:
\[ \text{C}_4\text{H}_8 (g) \longrightarrow 2\text{C}_2\text{H}_4 (g) \]
is characterized by an activation energy of 262 kJ/mol. At a temperature of 600.0 K, the rate constant, \( k \), is \( 6.1 \times 10^{-8} \, \text{s}^{-1} \). The question posed is to determine the value of the rate constant at 750.0 K.
A student attempted to solve the problem and submitted the following answer for the rate constant (\( k \)):
\[ k = 1.34 \times 10^3 \, \text{s}^{-1} \]
However, this answer is marked as incorrect.
---
To solve this problem correctly, one could use the Arrhenius equation:
\[ k = A e^{-\frac{E_a}{RT}} \]
where:
- \( k \) is the rate constant,
- \( A \) is the pre-exponential factor or frequency factor,
- \( E_a \) is the activation energy,
- \( R \) is the universal gas constant (8.314 J/mol·K),
- \( T \) is the temperature in Kelvin.
By substituting the given values of activation energy (\( E_a = 262 \, \text{kJ/mol} \)), and the temperatures (initial \( T_1 = 600.0 \, \text{K} \) and final \( T_2 = 750.0 \, \text{K} \)), we can apply the two-point form of Arrhenius equation:
\[ \ln \left(\frac{k_2}{k_1}\right) = \frac{E_a}{R} \left(\frac{1}{T_1} - \frac{1}{T_2}\right) \]
Given:
- \( k_1 = 6.1 \times 10^{-8} \, \text{s}^{-1} \)
- \( E_a = 262 \, \text{kJ/mol} = 262000 \, \text{J/mol} \)
After solving for](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F86546da6-58c7-4384-8a8e-1318a5c89f9f%2Fc4ab7cbb-53e5-4210-8377-3b9ab41f6b2b%2F8ijbnd_processed.png&w=3840&q=75)
Transcribed Image Text:### General Chemistry 4th Edition
### McQuarrie • Rock • Gallogly
### University Science Books presented by Macmillan Learning
---
### Reaction Analysis
The reaction:
\[ \text{C}_4\text{H}_8 (g) \longrightarrow 2\text{C}_2\text{H}_4 (g) \]
is characterized by an activation energy of 262 kJ/mol. At a temperature of 600.0 K, the rate constant, \( k \), is \( 6.1 \times 10^{-8} \, \text{s}^{-1} \). The question posed is to determine the value of the rate constant at 750.0 K.
A student attempted to solve the problem and submitted the following answer for the rate constant (\( k \)):
\[ k = 1.34 \times 10^3 \, \text{s}^{-1} \]
However, this answer is marked as incorrect.
---
To solve this problem correctly, one could use the Arrhenius equation:
\[ k = A e^{-\frac{E_a}{RT}} \]
where:
- \( k \) is the rate constant,
- \( A \) is the pre-exponential factor or frequency factor,
- \( E_a \) is the activation energy,
- \( R \) is the universal gas constant (8.314 J/mol·K),
- \( T \) is the temperature in Kelvin.
By substituting the given values of activation energy (\( E_a = 262 \, \text{kJ/mol} \)), and the temperatures (initial \( T_1 = 600.0 \, \text{K} \) and final \( T_2 = 750.0 \, \text{K} \)), we can apply the two-point form of Arrhenius equation:
\[ \ln \left(\frac{k_2}{k_1}\right) = \frac{E_a}{R} \left(\frac{1}{T_1} - \frac{1}{T_2}\right) \]
Given:
- \( k_1 = 6.1 \times 10^{-8} \, \text{s}^{-1} \)
- \( E_a = 262 \, \text{kJ/mol} = 262000 \, \text{J/mol} \)
After solving for
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