The reaction described by the equation 03(g) + NO(g) → O₂(g) + NO₂(g) has, at 310 K, the rate law rate of reaction = k[03][NO] k = 3.0 x 106 M-¹.s-¹ Given that [0₂] = 4.0 x 10-4 M and [NO] = 6.0 x 10-5 M at t = 0, calculate the rate of the reaction at t = 0. rate: What is the overall order of this reaction? 2 1 3 0 M/S
The reaction described by the equation 03(g) + NO(g) → O₂(g) + NO₂(g) has, at 310 K, the rate law rate of reaction = k[03][NO] k = 3.0 x 106 M-¹.s-¹ Given that [0₂] = 4.0 x 10-4 M and [NO] = 6.0 x 10-5 M at t = 0, calculate the rate of the reaction at t = 0. rate: What is the overall order of this reaction? 2 1 3 0 M/S
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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![**Chemical Kinetics: Reaction Rate and Order**
The reaction described by the equation:
\[ \text{O}_3(g) + \text{NO}(g) \rightarrow \text{O}_2(g) + \text{NO}_2(g) \]
At 310 K, the rate law is given by:
\[ \text{rate of reaction} = k[\text{O}_3][\text{NO}] \]
\[ k = 3.0 \times 10^6 \, \text{M}^{-1} \text{s}^{-1} \]
Given initial concentrations:
- \([\text{O}_3] = 4.0 \times 10^{-4} \, \text{M}\)
- \([\text{NO}] = 6.0 \times 10^{-5} \, \text{M}\)
Calculate the rate of the reaction at \( t = 0 \).
**Rate Calculation:**
\[
\text{rate} = \left(3.0 \times 10^6 \, \text{M}^{-1} \text{s}^{-1}\right) \times \left(4.0 \times 10^{-4} \, \text{M}\right) \times \left(6.0 \times 10^{-5} \, \text{M}\right)
\]
\[
\text{rate} = \left(3.0 \times 10^6\right) \times \left(2.4 \times 10^{-8}\right) \, \text{M/s}
\]
\[
\text{rate} = 7.2 \times 10^{-2} \, \text{M/s}
\]
**What is the overall order of this reaction?**
- [ ] 2
- [ ] 1
- [ ] 3
- [ ] 0
The overall order of the reaction is determined by adding the exponents in the rate law, which are 1 for \([\text{O}_3]\) and 1 for \([\text{NO}]\). Therefore, the overall order is 2.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F00154cd9-82c7-455b-845c-02cf21fdb65c%2F576cdd28-e56e-46a4-828a-5ecaccaba2d5%2F4ocg0g_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Chemical Kinetics: Reaction Rate and Order**
The reaction described by the equation:
\[ \text{O}_3(g) + \text{NO}(g) \rightarrow \text{O}_2(g) + \text{NO}_2(g) \]
At 310 K, the rate law is given by:
\[ \text{rate of reaction} = k[\text{O}_3][\text{NO}] \]
\[ k = 3.0 \times 10^6 \, \text{M}^{-1} \text{s}^{-1} \]
Given initial concentrations:
- \([\text{O}_3] = 4.0 \times 10^{-4} \, \text{M}\)
- \([\text{NO}] = 6.0 \times 10^{-5} \, \text{M}\)
Calculate the rate of the reaction at \( t = 0 \).
**Rate Calculation:**
\[
\text{rate} = \left(3.0 \times 10^6 \, \text{M}^{-1} \text{s}^{-1}\right) \times \left(4.0 \times 10^{-4} \, \text{M}\right) \times \left(6.0 \times 10^{-5} \, \text{M}\right)
\]
\[
\text{rate} = \left(3.0 \times 10^6\right) \times \left(2.4 \times 10^{-8}\right) \, \text{M/s}
\]
\[
\text{rate} = 7.2 \times 10^{-2} \, \text{M/s}
\]
**What is the overall order of this reaction?**
- [ ] 2
- [ ] 1
- [ ] 3
- [ ] 0
The overall order of the reaction is determined by adding the exponents in the rate law, which are 1 for \([\text{O}_3]\) and 1 for \([\text{NO}]\). Therefore, the overall order is 2.
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