Consider the reaction:2NH3(g) + 202(g) → N₂O(g) + 3H₂O(!)Using standard thermodynamic data at 298 K, calculate the entropy change for the surroundings when 1.85 moles of NH3 (9) react at standard conditions.Substance AH (kJ/mol)NH₁(9)-46.102 (9)0.0N₂O(g)82.1H₂O(!)-285.8J/KAS°surroundings

To find the entropy change for the surroundings, use the relationship between heat (q in joules) and…

Answered: Consider the reaction: 2NH3(g) + 202(g)…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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The decomposition of nitrogen pentoxide in the reaction 2N₂O5 (s)→ 4NO2(g) + O2(g) is endothermic with AH = +110 kJ/mol. Even so, this reaction is spontaneous for temperatures above 230 K because the change of a solid into a gas is a large increase of entropy.
i need help with these pleasee Consider the reaction: 2NH3(g) +202(g) → N₂O(g) + 3H₂O(1) Using standard thermodynamic data at 298 K, calculate the entropy change for the surroundings when 1.64 moles of NH3(g) react at standard conditions. ΔS Substance AH (kJ/mol) NH3(g) As O₂(g) N₂O(g) H₂O (1) surroundings Consider the reaction: system -46.1 0.0 82.1 -285.8 H₂CO(g) + O2(g) → CO₂(g) + H₂O(1) Using standard absolute entropies at 298 K, calculate the entropy change for the system when 1.63 moles of H₂CO(g) react at standard conditions. J/K J/K Substance Sº (J/K mol) H₂CO(g) 219.0 0₂ (9) 205.1 CO₂(g) 213.7 H₂O(l) 69.9 SUVIL
Consider the reaction: 4HCl(g) + O₂(g) → 2H₂O(g) + 2Cl₂ (g) Using standard absolute entropies at 298 K, calculate the entropy change for the system when 1.69 moles of HCl(g) react at standard conditions. AS⁰ Substance So (J/K mol) HCl(g) 186.9 O2(g) 205.1 H₂O(g) 188.8 Cl₂ (g) 223.1 system = J/K
Round everthing to 4 decimal places. Ammonia and carbon dioxide are produced from the hydrolysis of urea, the corresponding chemical reaction shown below:
Consider the reactionS(s,rhombic) + 2CO(g)SO2(g) + 2C(s,graphite)for which H° = -75.80 kJ and S° = -167.6 J/K at 298.15 K.(1) Calculate the entropy change of the UNIVERSE when 1.716 moles of S(s,rhombic) react under standard conditions at 298.15 K. Suniverse = J/K (2) Is this reaction reactant or product favored under standard conditions?(3) If the reaction is product favored, is it enthalpy favored, entropy favored, or favored by both enthalpy and entropy? If the reaction is reactant favored choose 'reactant favored'.
Using the provided data, determine the temperatures at which the following hypothetical reaction will be spontaneous under standard conditionsA + B → 2C + D△S°rxn = 249.1 J/K△H°rxn = 104.6 kJ * at no temperatures * at all temperatures below 146.9 °C * at all temperatures above 146.9 °C * at all temperatures above 238.1 °C * at all temperatures below 238.1 °C * at all temperatures
Consider the reaction: Fe2O3(s) + 2Al(s) → Al2O3 (s) + 2Fe(s) Using standard thermodynamic data at 298 K, calculate the entropy change for the surroundings when 2.00 moles of Fe₂O3(s) react at standard conditions. AS⁰ Substance AH (kJ/mol) Fe₂O3(s) -824.2 Al(s) 0.0 Al2O3(s) -1675.7 Fe(s) 0.0 surroundings J/K
For the following reaction (the detonation of nitroglycerin), is it spontaneous under standard conditions and how can you tell? 4 C4H5N3O9(l) (arrow >) 12 CO2(g) + 10 H2O(g) + 6 N2(g) + O2(g) ΔH = -5678 kJ
Consider the reaction Fe(s) + 2HCl(aq) → FeCl₂ (s) + H₂(g) for which AH = -7.400 kJ and AS = 107.9 J/K at 298.15 K. 1. Calculate the entropy change of the UNIVERSE when 2.385 moles of Fe(s) react under standard conditions at 298.15 K. ASuniverse J/K 2. Is this reaction reactant or product favored under standard conditions? 3. If the reaction is product favored, is it enthalpy favored, entropy favored, or favored by both enthalpy and entropy? If the reaction is reactant favored, choose 'reactant favored'. Submit Answer Retry Entire Group 5 more group attempts remaining
Consider the reaction: 6CO2(g) + 6H₂O(l) → C6H12O6 + 602 (9) Using standard thermodynamic data at 298 K, calculate the entropy change for the surroundings when 1.87 moles of CO₂ (g) react at standard conditions. AS⁰ Substance AH (kJ/mol) CO₂ (g) -393.5 H₂O(1) -285.8 C6H12O6 -1275.0 O₂(g) 0.0 surroundings J/K
Given the following reaction, calculate the standard entropy at 25oC. 2NO(g) + O2(g) 2NO2(g) (Sof NO2 = 240.1 J mol-1K-1; Sof NO = 210.8 J mol-1K-1; Sof O2 = 205.1 J mol-1K-1)
[Review Topics] [References] Use the References to access important values if needed for this question. Consider the reaction: 2HBr(g) → H₂(g) + Br₂ (1) Using standard thermodynamic data at 298 K, calculate the free energy change when 2.01 moles of HBr(g) react at standard conditions. AGO rxn Substance AG (kJ/mol) HBr(g) H₂(g) Br₂ (1) = -53.5 0.0 0.0 KJ Retry Entire Group Submit Answer 9 more group attempts remaining

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