Consider the reaction:H₂CO(g) + O₂(g) → CO₂(g) + H₂O(1)Using standard absolute entropies at 298 K, calculate the entropy change for the system when 2.42 moles of H₂CO(g) react atstandard conditions.20ASSubstance Sº (J/K mol)H₂ CO(g)219.00₂ (9)205.1CO₂(g)H₂O (1)213.769.9systemSubmit Answer888RV%J/KShow Hint5Retry Entire Group[Review Topics][References]Use the References to access important values if needed for this question.TGBCengage Learning | Cengage Technical Support6Y9 more group attempts remainingH&7NUJ00 *8M(9K其LEPPreviousTEmail Instructor Save and Exit{[Next?delete

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onsider the reaction: H₂CO(g) + O₂(g) → CO₂(g) + H₂O(1) Using standard absolute entropies at 298 K, calculate the entropy change for the system when 2.42 moles of H₂CO(g) react at standard conditions. ASO Substance Sº (J/K mol) H₂CO(g) 219.0 02 (g) 205.1 CO₂(g) 213.7 H₂O(1) 69.9 system Submit Answer [Review Topics] [References] Use the References to access important values if needed for this question. J/K Retry Entire Group Show Hint 9 more group attempts remaining Cengage Learning | Cengage Technical Support Previous Next Email Instructor Save and Exit

onsider the reaction: H₂CO(g) + O₂(g) → CO₂(g) + H₂O(1) Using standard absolute entropies at 298 K, calculate the entropy change for the system when 2.42 moles of H₂CO(g) react at standard conditions. ASO Substance Sº (J/K mol) H₂CO(g) 219.0 02 (g) 205.1 CO₂(g) 213.7 H₂O(1) 69.9 system Submit Answer [Review Topics] [References] Use the References to access important values if needed for this question. J/K Retry Entire Group Show Hint 9 more group attempts remaining Cengage Learning | Cengage Technical Support Previous Next Email Instructor Save and Exit

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Standard Entropy of Reaction Molecular systems tend to move spontaneously to a state of maximum randomness or disorder. Molecular randomness, or disorder, is called entropy and is denoted by the symbol S. As a state function, entropy change, A.S. depends only on initial and final states. AS has a positive value when disorder increases and a negative value when disorder decreases. The following conditions usually result in an increase in entropy: • a change of phase: solid-liquid-gas, an increase in the number of gas molecules, or • a solid dissolving to form a solution. Although the sign of the entropy change can be predicted as described above, the actual value of AS° must be calculated from the absolute entropy values. Sº, of the reactants and products: ASS° (products) - S° (reactants) ▼ Part A Predict the sign of the entropy change. AS°, for each of the reaction displayed. Drag the appropriate items to their respective bins. ▸ View Available Hint(s) Positive Submit H₂O(1) H₂O(g)…
Consider the reaction: 4HCl(g) + O₂(g) → 2H₂O(g) + 2Cl₂ (g) Using standard absolute entropies at 298 K, calculate the entropy change for the system when 1.69 moles of HCl(g) react at standard conditions. AS⁰ Substance So (J/K mol) HCl(g) 186.9 O2(g) 205.1 H₂O(g) 188.8 Cl₂ (g) 223.1 system = J/K
2 NH3 (g) + 2 O2 (g) → N20 (g) + 3 H2O (g) Is this reaction spontaneous only at low temperatures, only at high temperatures, at all temperatures? AH°r, kJ/mol s°, J/mol·K NH3(g) -46.1 192.5 0:(g) 205.0 N 20 (g) 82.1 219.9 H2O(g) |-241.8 188.7 AH°i, kJ/mol s°, J/mol·K What is the lowest temperature at which the following reaction is spontaneous? H2O (g) + C (s) → H2 (g) + CO (g) Co(g) H2(g) C (s) -110.5 | 197.7 130.6 5.7 H2O(g) |-241.8 188.7
Ip acellus_engine.html?ClassID=D1653724337# Calculate the entropy of the phase change of uranium hexafluoride from gas to solid. UF6(g) → UF6(s) Substance S° (J/mol-K) UF (s) UF (g) ASiep = [ ? ] J/mol - K 228 380 Enter either a + or - sign AND the magnitude in your answer. Enter
For the following reaction (the detonation of nitroglycerin), is it spontaneous under standard conditions and how can you tell? 4 C4H5N3O9(l) (arrow >) 12 CO2(g) + 10 H2O(g) + 6 N2(g) + O2(g) ΔH = -5678 kJ
Calculate entropy change of a sample of 20 g of ice when it melts at 0oC under pressure of 1 atm. (fus H (H2O) = 6.0 kJ mol-1)
Enter your answer in the provided box. Calculate the standard entropy change for the following reaction at 25°C. 2 Al(s) + 3 ZnO(s) → Al₂O3(s) + 3 Zn(s) Substance Al(s) Al³+ (aq) Al₂O3(s) Zn(s) Zn²+ (aq) ZnO(s) J/K Sº (J/K mol) 28.3 -313.38 50.99 41.6 -106.48 43.9 27
What is the temperature at which the reaction below becomes spontaneous, if the standard entropies of reactants and products at 25oC are So (C(gr)) = 5.74 J/mol*K, So(H2(g)) = 130.68 J/mol*K, and So (C8H8(g)) = 345.2600J/mol*K and the heat of formation of C8H8(g)) is 147.8500 kJ/mol?C8H8(g) ↔ 8C(gr) + 4H2(g)a)661.88 Kb)707.958 Kc)the reaction is never spontaneousd)the reaction is always spontaneous
Calculate the temperature at which the following reaction becomes spontaneous. Compound ΔHof (kJmol)ΔHfo (kJmol) ΔSo (JK ⋅ mol)ΔSo (JK ⋅ mol) Cl2(g) 0.0 +223.1 ClNO2(g) +12.6 +272.2 NO(g) +91.3 +210.8 NO2(g) +33.2 +240.1 NOCl(g) +51.7 +261.7 PCl3(g) −287.2 +311.8 PCl5(g) −374.9 +364.6 PCl5(g) ↔ PCl3(g) + Cl2(g) (Answer with K unit )
Consider the following reaction: C(graphite) + 1/2 O2 (g) → CO(g) Is it spontaneous under standard conditions at 298 K? Answer this question by calculating AS" (system), AS° (surroundings), and AS (universe). (Define reactants and products as the system.) S* (J/mol · K) A¡H° (kJ/mol) at 298 K (kJ/mol) Compound at 298 K C(s, graphite) 5.6 CO(g) 197.674 -110.525 CS2 (g) 237.8 116.7 CCL (e) 214.39 -128.4 Cl2 (g) 223.08 Si(s) 18.82 SİCL, (g) 330.86 -662.75 S(s, rhombic) 32.1 Br2 (e) 152.2 HBr(g) 198.70 -36.29 H2 (g) 130.7 H2O2 (e) 109.6 -187.78 O2 (g) 205.07 O yes O no