Using the following data, give an approximation of the temperature at which the reaction CH4 (g) + 4 Cl2 (g) --- CCl4 (g) + 4 HCl (g) would be spontaneous and indicate what assumptions were made to elicit your answer.

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Using the following data, give an approximation of the temperature at which the reaction CH4 (g) + 4 Cl2 (g) --- CCl4 (g) + 4 HCl (g) would be spontaneous and indicate what assumptions were made to elicit your answer.
(JK´'mol·1)
186.26
énergie moyenne
(kJ/mol)
432
427
liaisons
Molécule
S°m
CH4 (g)
CI (g)
Cl2 (g)
CCI4 (g)
CCI4 (1)
HCI (g)
HС (ag)
chimiques
H-H
H-CI
165.20
223.07
309.65
C-H
413
С —С
C = C
C-CI
347
216.40
614
186.91
339
56.5
CI-CI
239
Transcribed Image Text:(JK´'mol·1) 186.26 énergie moyenne (kJ/mol) 432 427 liaisons Molécule S°m CH4 (g) CI (g) Cl2 (g) CCI4 (g) CCI4 (1) HCI (g) HС (ag) chimiques H-H H-CI 165.20 223.07 309.65 C-H 413 С —С C = C C-CI 347 216.40 614 186.91 339 56.5 CI-CI 239
Expert Solution
Step 1

According to second law of thermodynamics , entropy of a system always Increases. Or the value of entropy should be positive for an spontaneous process. 

While if the entropy change value is negative , means system will tend to ordered manner, then Reaction is non spontaneous.

 

Given that - 

CH4 (g) + 4Cl2 (g) ---> CCl4 (g) + 4HCl (g) 

 

For this Reaction the entropy change for the Reaction can be calculated by - 

∆S° = S°products - S°reactants 

Also given that - 

Entropies of substances are - 

CH4(g) = 186.26 JK-1 mol-1 

Cl2(g) = 223.07 JK-1 mol-1 

CCl4(g) = 309.65 JK-1 mol-1 

HCl(g) = 186.91 JK-1 mol-1 

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