Consider the reaction Fe2O3(s) + 2Al(s) Al2O3(s) + 2Fe(s) for which AH° = -851.5 kJ and AS° = -37.00 J/K at 298.15 K. (1) Calculate the entropy change of the UNIVERSE when 1.699 moles of Fe2O3(s) react under standard conditions at 298.15 K. AS universe = J/K (2) Is this reaction reactant or product favored under standard conditions? (3) If the reaction is product favored, is it enthalpy favored, entropy favored, or favored by both enthalpy and entropy? If the reaction is reactant favored choose 'reactant favored'. Submit Answer
Consider the reaction Fe2O3(s) + 2Al(s) Al2O3(s) + 2Fe(s) for which AH° = -851.5 kJ and AS° = -37.00 J/K at 298.15 K. (1) Calculate the entropy change of the UNIVERSE when 1.699 moles of Fe2O3(s) react under standard conditions at 298.15 K. AS universe = J/K (2) Is this reaction reactant or product favored under standard conditions? (3) If the reaction is product favored, is it enthalpy favored, entropy favored, or favored by both enthalpy and entropy? If the reaction is reactant favored choose 'reactant favored'. Submit Answer
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:Consider the reaction
Fe2O3(s) + 2Al(s)—>Al2O3(s) + 2Fe(s)
for which AH° = -851.5 kJ and AS° = -37.00 J/K at 298.15 K.
(1) Calculate the entropy change of the UNIVERSE when 1.699 moles of Fe2O3(s) react under standard
conditions at 298.15 K.
AS universe ==
J/K
(2) Is this reaction reactant or product favored under standard conditions?
(3) If the reaction is product favored, is it enthalpy favored, entropy favored, or favored by both enthalpy and
entropy? If the reaction is reactant favored choose 'reactant favored'.
Submit Answer
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