Consider the following reaction catalyzed by Phosphopentose Epimerase at 37 oC. Xylulose 5-phosphate ---> Ribulose 5-phosphate At equilibrium, the ratio of Xylulose 5-P / Ribulose 5-P = 1/18.85 Calculate K’eq.
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- Consider the following reaction catalyzed by Phosphopentose Epimerase at 37 oC. Xylulose 5-phosphate ---> Ribulose 5-phosphate At equilibrium, the ratio of Xylulose 5-P / Ribulose 5-P = 1/18.85 Calculate K’eq.Consider the following reaction catalyzed by Phosphopentose Epimerase at 37 oC. Xylulose 5-phosphate ---> Ribulose 5-phosphate At equilibrium, the ratio of Xylulose 5-P / Ribulose 5-P = 1/18.85 The physiological concentration of Xylulose 5-phosphate is 0.019 mM and the physiological concentration of of Ribulose 5-phosphate is 2.940 mM. Which direction would the reaction proceed as written under physiological conditions?Consider the following reaction catalyzed by Phosphopentose Epimerase at 37 oC. Xylulose 5-phosphate ---> Ribulose 5-phosphate At equilibrium, the ratio of Xylulose 5-P / Ribulose 5-P = 1/18.85 The physiological concentration of Xylulose 5-phosphate is 0.019 mM and the physiological concentration of of Ribulose 5-phosphate is 2.940 mM. Calculate ΔG.
- Determine the branch points and reducing ends of amylopectin. A 0.5g sample of amylopectin was analyzed to determine the fraction of the total glucose residues that are branch points in the structure. The sample was methylated and then digested, yielding 50 μmol of 2,3-methylglucose and 0.4 μmol of 1,2,3,6-tetramethyl glucose. (MWglucose = 162 g/mol, minus H2O) What fraction of the total residues are branch points? How many reducing ends does the amylopectin have?Inositol hexaphosphate (phytic acid, InsP6) is converted to 5-InsP7 by the action of the enzyme IP6K using adenosine 5'-triphosphate (ATP) as the substrate. What is the byproduct (indicated by ?) in the reaction? 2-O3PO OPO,2- InsPs 2-O3PO 5-InsP7 IP6K OPO,2- 2-O3PO- FOPO32 0- FOPO,2 2-03PO- OPO,2 OPO,2- АТР ? adenosine adenosine 5'-monophosphate adenosine 5'-diphosphate adenineThe disaccharide lactulose consists of a D-galactopyranose subunit and a D-fructofuranose subunit joined by a B-1,4'-glycosidic linkage. After treatment of lactulose with 1. excess CH3I/Ag20, 2. HCI/H20, the D-galactopyranose subunit was found to have one nonmethylated OH group, whereas the D-fructofuranose subunit had two. Draw the structure of a-lactulose.
- The disaccharide lactulose consists of a d-galactopyranose subunit and a d-fructofuranose subunit joined by a β-1,4-glycosidic linkage. After treatmentof lactulose with 1. excess CH3I/Ag2O, 2. HCl/H2O, the d-galactopyranose subunit was found to have one nonmethylated OH group, whereas thed-fructofuranose subunit had two. Draw the structure of α-lactulose.C6H12O6 + a*O2 + b*NH3 --> c*CH1.64O0.52N0.16 + d*CO2 + e*H2O + f*C2H5OH In the aerobic yeast growth process, overflow metabolism can be observed when the sugar feed rate exceeds the oxidizing capacity of the yeast. In this case, part of the substrate is treated anaerobically and the production of biomass is reduced and ethanol is formed. This can also be observed when the respiratory rate RQ goes above one. The chemical composition of this yeast is CH1.64O0.52N0.16 . The yield of ethanol from glucose is 0.14 g g-1 and the yield of biomass from glucose is 0.362 g g-1. Calculate the oxygen demand of the reaction. In this calculation, use the following rounded even values as atomic weights for all calculations: C=12 g/mol, H=1 g/mol, O=16 g/mol ja N=14 g/mol. So how many moles of oxygen are needed per mole of glucose?Give a clear handwritten answer..?
- Draw the structure of: (a) a polysaccharide formed by joining D-mannose units in 1->4-ß-glycosidic linkages; (b) a polysaccharide formed by joining D-glucose units in 1->6-a-glycosidic linkages. The polysaccharide in (b) is dextran, a component of dental plaque.A. Classify each of the following monosaccharides as aldose or ketose. (a) H. (b) CH2OH (c) CH2OH (d) H. C=0 C=0 HO-C-H H-C-H H-C-OH HO-C-H H-C-OH H-C-OH H-C-OH HO-C-H CH2OH H-C-OH CH2OH H-C-OH | CH2OH CH2OH Threose Ribulose Tagatose 2-DeoxyriboseResearchers analysed a glycopeptide (a peptide carrying one or several oligosaccharide groups) and determined both the sequence of the peptide and the sequence of the sugar molecule. The latter was identified as a diholoside coupled to the peptide by an osidic bond. The systematic name of this sugar is: B-D-glucopyranosyl-(1→4)-ß-D-galactopyranose. : Represent the chemical formula of this diholoside in a way that all oses are Question 1 represented according to the Haworth convention. Apart from the furane and/or pyrane cycles all atoms of this molecule must be given.
