Consider the following reaction catalyzed by Phosphopentose Epimerase at 37 °C. Xylulose 5-phosphate ---> Ribulose 5-phosphate At equilibrium, the ratio of Xylulose 5-P/Ribulose 5-P = 1/18.85 The physiological concentration of Xylulose 5-phosphate is 0.019 mM and the physiological concentration of of Ribulose 5-phosphate is 2.940 mM. Calculate AG. Type your answer...

C6H12O6 + a*O2 + b*NH3 --> c*CH1.64O0.52N0.16 + d*CO2 + e*H2O + f*C2H5OH In the aerobic yeast growth process, overflow metabolism can be observed when the sugar feed rate exceeds the oxidizing capacity of the yeast. In this case, part of the substrate is treated anaerobically and the production of biomass is reduced and ethanol is formed. This can also be observed when the respiratory rate RQ goes above one. The chemical composition of this yeast is CH1.64O0.52N0.16 . The yield of ethanol from glucose is 0.14 g g-1 and the yield of biomass from glucose is 0.362 g g-1. Calculate the oxygen demand of the reaction. In this calculation, use the following rounded even values as atomic weights for all calculations:  C=12 g/mol, H=1 g/mol, O=16 g/mol ja N=14 g/mol.  So how many moles of oxygen are needed per mole of glucose?

Inositol hexaphosphate (phytic acid, InsP6) is converted to 5-InsP7 by the action of the enzyme IP6K using adenosine 5'-triphosphate (ATP) as the substrate. What is the byproduct (indicated by ?) in the reaction? 2-O3PO OPO,2- InsPs 2-O3PO 5-InsP7 IP6K OPO,2- 2-O3PO- FOPO32 0- FOPO,2 2-03PO- OPO,2 OPO,2- АТР ? adenosine adenosine 5'-monophosphate adenosine 5'-diphosphate adenine

classify the following monosaccharides as aldoses/ketoses, triose/tetrose/pentose/hexose/ L/D enantiomer, and a-/Banomer when applicable.

ujqu2)allempl.php?at tempt=3738793& cmid3 38528 58 pa e=21 O. но CH но но но When this disaccharide is formed.... но Select one: Но O a. An alpha-beta-1,2-glycosidic bond is created O b. Glucose and galactose are bonded together Oc. A beta-1,4-glycosidic linkage is created O d. A hemiacetal bond in the molecule's center splits Time left 1:24:21 A water molecule is released

A. Classify each of the following monosaccharides as aldose or ketose. (a) H. (b) CH2OH (c) CH2OH (d) H. C=0 C=0 HO-C-H H-C-H H-C-OH HO-C-H H-C-OH H-C-OH H-C-OH HO-C-H CH2OH H-C-OH CH2OH H-C-OH | CH2OH CH2OH Threose Ribulose Tagatose 2-Deoxyribose

Draw the structure of: (a) a polysaccharide formed by joining D-mannose units in 1->4-ß-glycosidic linkages; (b) a polysaccharide formed by joining D-glucose units in 1->6-a-glycosidic linkages. The polysaccharide in (b) is dextran, a component of dental plaque.

What carbohydrates is/are in your unknown? my unknown is sucrose Identifying an Unknown Carbohydrate Unknown No. Sucrose Results with Unknown Benedict's (A) Seliwanoff's (B) Fermentation (C) Iodine (D) negative Positive Positive negative Possible Sugars Present Sucrose + H₂0 starch + 420. sucrose and fructose Glucose, fructose, Sucrosé starch sucroset HCI

Understanding the optical rotation that we observe in lab is not the same as the specific rotation commonly reported in the literature; a student sets out to explore this on their own. They prepare a 0.083 g/mL sucrose solution, pour it into a 1 dm long optical cell, and measure the optical rotation of this solution to be 5.5 degrees. Use Biot's law to determine the specific rotation of sucrose and then the percent difference in compare this experimentally determined value against the accepted value provided above. Biot's law states www απ [a]lc where a is the observed optical rotation in units of degrees, 1 is the length of the cell in units of decimeters (dm), c is the sample concentration in units of grams per milliliter (g/mL), and [a] is the specific rotation in units of degrees (the formal unit for specific rotation is degrees divided by dmg/mL, but scientific literature uses just degrees). Percent difference = |Experimental value-Accepted value| Accepted value × 100%

Calculate the ΔGo’ for the following reaction at 37 oC: Galactose + Glucose → Lactose    + H2O       K’eq = 0.002089