NH3 is normally encountered as a gas with a pungent odor. It is formed from hydrogen and nitrogen (equation given below). A chemist pours a mixture of nitrogen gas and hydrogen gas in a 1.0 litre reaction vessel in 1:3 ratio. The equilibrium constant for the reaction is 9.7 × 10 −³, and the equilibrium value of [H2(g)] is 0.91 mol/L. Calculate the equilibrium value of [NH]. N2(g) + 3 H2(g) ⇒ 2 NH2(g)

World of Chemistry, 3rd edition
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Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
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Chapter17: Equilibrium
Section: Chapter Questions
Problem 17A
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NH3 is normally encountered as a gas with a pungent odor. It is
formed from hydrogen and nitrogen (equation given below). A
chemist pours a mixture of nitrogen gas and hydrogen gas in a 1.0
litre reaction vessel in 1:3 ratio. The equilibrium constant for the
reaction is 9.7 × 10 −³, and the equilibrium value of [H2(g)] is 0.91
mol/L. Calculate the equilibrium value of [NH].
N2(g) + 3 H2(g) ⇒ 2 NH2(g)
Transcribed Image Text:NH3 is normally encountered as a gas with a pungent odor. It is formed from hydrogen and nitrogen (equation given below). A chemist pours a mixture of nitrogen gas and hydrogen gas in a 1.0 litre reaction vessel in 1:3 ratio. The equilibrium constant for the reaction is 9.7 × 10 −³, and the equilibrium value of [H2(g)] is 0.91 mol/L. Calculate the equilibrium value of [NH]. N2(g) + 3 H2(g) ⇒ 2 NH2(g)
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