Consider the circuit shown in the figure below, where C1 = 8.00 µF, C2 = 6.00 µF, and ΔV = 22.0 V. Capacitor C1 is first charged by closing switch S1. Switch S1 is then opened, and the charged capacitor is connected to the uncharged capacitor by closing S2. Consider the circuit shown in the figure below, where C, = 8.00 µF, C, = 6.00 µF, and AV = 22.0 V. Capacitor C, is first charged by closing switch S,. Switch S, is then opened, and the charged capacitor is connected to theuncharged capacitor by closing S,.AVS,S2(a) Calculate the initial charge (in uC) acquired by C,. (Round your answer to at least one decimal place.)176(b) Calculate the final charge (in pC) on each capacitor. (Round your answers to at least the nearest integer.)Q, = 94.7What is the equivalent capacitance of the two capacitors when switch S, is closed? µCQ2You are correct that the sum of the charges on C, and C, must be the same as the original charge on C,. µC81.23(c) What If? After a very long time, switch s, is also closed. By what amount does the charge on the second capacitor change after S, has been closed for a very long time? (Give your answer in uC.)132|x pC

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Answered: Consider the circuit shown in the…

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