In the circuit shown below, after the switch has been closed for a long time the energy stored in both capacitors combined is 21.4µJ. 2.0µF 4.0µF 100 Determine the emf of the battery. 9.10 V 1.74 V 5.66 V 2.80 V 3.20 V ОООО
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- A 22.0 V battery moves 7.6 KC of charge. How much energy does the battery deliver? A 2.9x10-³J B 3.5 x 10² J C 1.7 x 105 J D 1.4 x 10¹¹ JIn the circuit shown in the figure attached each capacitor initially has a charge of magnitude 4.00 nC on its plates. a) After the switch S is closed, what will be the current in the circuit at the instant that the capacitors have lost 80.0% of their initial stored energy?10
- The capacitor in the circuit is initially uncharged. The switch closes at time t = 0. 4.7 kQ The potential across the capacitor as a function of time is given below. Voltage (V) -10 0.002 0.004 0.006 0.008 Time (s) Use the graph to estimate the battery_potential.A portion of a circuit is shown in the figure, and the batteries have no internal resistance. What is the potential difference VA - VB if I = 5.0 A?A 16.0 µF Capacitor is charged to Qo. It is then connected in a simple loop circuit with a 265 Q resistor (and nothing else). How much time does it take for the capacitor to reach 25% of its initial charge? O 5.88 ms O 9.03 ms O 4.24 ms O 1.22 ms
- Two resistors are arranged in a circuit, as shown below. 24-volt 4.0 2 6.0 Q source48 V + #F 68 ΚΩ www Ic + 20 www. 0 0000 1 22 ΚΩ = 10 nF 12 V Assume the capacitor to be fully discharged before the switch closes to position 1 at t=0: D. Determine equations for Ic(t) and Vc(t) in position 1. After a long time (i.e. >5 T, capacitor fully charged) the switch is moved to position 2: E. Determine equations for Ic(t) and Vc(t) in position 2. F. Provide a sketch of Ic(t) and Vc(t) for both cycles. Please label accordingly. F VcThe circuit in the figure below contains two resistors, R, 2.20 kN and R, = 3.10 kN, and two capacitors, C, = 2.10 µF and C, = 3.10 µF, connected to a %D battery with emf & = 115 V. There are no charges on the capacitors before switch S is closed. R1 C1 7. R2 C2 3. (i (a) Determine the charge on capacitor C, as a function of time (in ms), after the switch is closed. (Use the following as necessary: t.) -t 5.15 HC 9, = %3D 598 1–e (b) Determine the charge on capacitor C, as a function of time (in ms), after the switch is closed. (Use the following as necessary: t.) HC 92 %3D
- The capacitor is initially uncharged when the switch is closed at t=0. When t equals 10s what does the ammeter read? (In mA) a.0.10 b. 0.20 c.0.79 d.1.2 e. 2E2 R1 R2 2. Find the charge on the capacitor after the switch has been left open for some time, then closed for some period of time. We can assume that C = 2 µF, with batteries of values E1 R2 = 0.25 N. 2V and E2 =1V, and resistor values R1 = 0.5 N and SThe figure shows a simple RC circuit consisting of a 100.0 V battery in series with a C = 10.0 μ F capacitor and a R = 4.3 × 105 resistor. Initially, the switch S is open and the capacitor is uncharged. 100.0 V A) 1.1 x 10-³ C B) 2.9 × 10-3 C C) 3.7 x 104 C D) 5.2 x 10-4 C E) 6.6 × 104 C I S R 10.0 µF How much charge q is on the capacitor 2.0 s after the switch is closed? (Hint: First compute the final charge on the capacitor and the RC circuit's time constant.)