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The circuit in the figure below contains two resistors, R, = 2.20 kn and R, = 3.10 kn, and two capacitors, C, = 2.10 µF and C, = 3.10 µF, connected to battery with emf E = 115 V. There are no charges on the capacitors before switch S is closed. R R2 C2 (a) Determine the charge on capacitor C, as a function of time (in ms), after the switch is closed. (Use the following as necessary: t.) (b) Determine the charge on capacitor C, as a function of time (in ms), after the switch is closed. (Use the following as necessary: t.) 92 =

The circuit in the figure below contains two resistors, R, = 2.20 kn and R, = 3.10 kn, and two capacitors, C, = 2.10 µF and C, = 3.10 µF, connected to battery with emf E = 115 V. There are no charges on the capacitors before switch S is closed. R R2 C2 (a) Determine the charge on capacitor C, as a function of time (in ms), after the switch is closed. (Use the following as necessary: t.) (b) Determine the charge on capacitor C, as a function of time (in ms), after the switch is closed. (Use the following as necessary: t.) 92 =

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The circuit in the figure below contains two resistors, \( R_1 = 2.20 \, \text{k}\Omega \) and \( R_2 = 3.10 \, \text{k}\Omega \), and two capacitors, \( C_1 = 2.10 \, \mu\text{F} \) and \( C_2 = 3.10 \, \mu\text{F} \), connected to a battery with emf \( \mathcal{E} = 115 \, \text{V} \). There are no charges on the capacitors before switch \( S \) is closed. ### Diagram Description: - The circuit diagram shows \( R_1 \) and \( R_2 \) in series, then in parallel with \( C_1 \) and \( C_2 \) also in series. - A switch \( S \) is shown open but is meant to be closed. - The battery provides an emf of 115 V. **(a)** Determine the charge on capacitor \( C_1 \) as a function of time (in ms), after the switch is closed. (Use the following as necessary: \( t \).) \[ q_1 = 598 \left( 1 - e^{\frac{-t}{5.13}} \right) \, \mu\text{C} \] **(b)** Determine the charge on capacitor \( C_2 \) as a function of time (in ms), after the switch is closed. (Use the following as necessary: \( t \).) \[ q_2 = \, \mu\text{C} \] (Note: The equation for \( q_2 \) is left unfilled in the image, indicating more information may be needed to complete this part of the problem.)
Transcribed Image Text:The circuit in the figure below contains two resistors, \( R_1 = 2.20 \, \text{k}\Omega \) and \( R_2 = 3.10 \, \text{k}\Omega \), and two capacitors, \( C_1 = 2.10 \, \mu\text{F} \) and \( C_2 = 3.10 \, \mu\text{F} \), connected to a battery with emf \( \mathcal{E} = 115 \, \text{V} \). There are no charges on the capacitors before switch \( S \) is closed. ### Diagram Description: - The circuit diagram shows \( R_1 \) and \( R_2 \) in series, then in parallel with \( C_1 \) and \( C_2 \) also in series. - A switch \( S \) is shown open but is meant to be closed. - The battery provides an emf of 115 V. **(a)** Determine the charge on capacitor \( C_1 \) as a function of time (in ms), after the switch is closed. (Use the following as necessary: \( t \).) \[ q_1 = 598 \left( 1 - e^{\frac{-t}{5.13}} \right) \, \mu\text{C} \] **(b)** Determine the charge on capacitor \( C_2 \) as a function of time (in ms), after the switch is closed. (Use the following as necessary: \( t \).) \[ q_2 = \, \mu\text{C} \] (Note: The equation for \( q_2 \) is left unfilled in the image, indicating more information may be needed to complete this part of the problem.)
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