Switch S1 has been closed and $2 has open for a long time until the capacitors are fully charged. At t-0, $1 is opened and S2 is closed. Ifs=12V, C₁-4mF and C₂-8mF, R₁-2.92k0 and R₂-3.25 k0; what is the current passing through R₂ at t-0 in units of mA? Please express your answer using two decimal places. 20 www 5. 11 C₂ a b
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- Three resistors, a battery and a capacitor are connected as shown below. Initially the switch 'S' is open for a long time, then at time t = 0 the switch is closed. Assuming R₁ = 4 N, R₂ = 6 N, R3 = 9 N, C = 23 µF, and V = 12 V, answer the following questions about the charging process in the circuit. R₂ ww V VI R₁ mm What is the maximum charge on the capacitor (at t→→ ∞)? The maximum charge, Qmax The time constant, t = = What is the time constant of this RC circuit? R₂ Units Select an answer ✓ Units Select an answer ✓ What is the charge on the capacitor at t = 202 μs? The charge, Q = Units Select an answer ✓ CV + R w с The switch in the figure is thrown so that the battery is in series with the resistor and an uncharged capacitor. After 1.9 time constants, what is the charge on the capacitor in terms of the maximum charge, Qo? Supply the missing numerical factor below. Q(1.9T) = ( )QoThe capacitor in the circuit is initially uncharged. The switch closes at time t = 0. 4.7 kQ The potential across the capacitor as a function of time is given below. Voltage (V) -10 0.002 0.004 0.006 0.008 Time (s) Use the graph to estimate the battery_potential.
- In the circuit, R= 30.0 kN and C = 0.100 µF. The capacitor is allowed to charge fully, and then the switch is changed from position a to position b. What will the voltage across the resistor be 8.40 ms later? R where X = 64.1 V.For the circuit shown in the figure, V = 20 V, C = 10 μF, R = 0.80 MQ, and the battery is ideal. Initially the switch S is open and the capacitor is uncharged. The switch is then closed at time t = 0.00 s. What is the charge across the capacitor 20 s after closing the switch? { www R O 0.18 mC O 1.5 mC O 0.48 mC O 3.0 MC O 2.3 MCFour identical capacitors are connected with a resistor in two different ways. When they are connected as in part a of the drawing, the time constant to charge up this circuit is 0.72 s. What is the time constant when they are connected with the same resistor as in part b? R C с Number i R www C + (b) Units
- What is the voltage change if you cross a resistor R in the same direction as the current I? (This means you want Vf-Vi, where Vi is the voltage where the current enters the resistor and Vf, is the voltage where the current leaves the resistor.) What is the voltage change if you cross a resistor R opposite the direction of the current I? (in this case, Vi is the voltage where the current leaves the resistor, and Vf is the voltage where the current enters the resistor.) Which answer is correct? +IR in both cases +IR in the first case and -IR in the second case. +IR in both cases -IR in the first case and +IR in the second case.Units are correct but my numerical answers are wrong. What am I doing wrong here?C2 C1 XS R 5. From the figure above, a pair of charged capacitors are given C1 and C2 = 2 µF which are charged with a battery of 12 V. Determine then, how much charge between both capacitors is left after the switch has closed for over 1ms? How much is left for the capacitors C1 and C2? Lastly, determine the . 1 μF current of the circuit after this time.
- Hand written solutions are strictly prohibited.Assume the capacitor in the circuit is initially uncharged. A) Calculate the current through each resistor right after the circuit is connected. B) Now let’s say, the circuit has been connected and left alone for a long time.Calculate the charge on the capacitor plate.In the circuit below, Vo = 27 V, V₁ = 11 V, R₁ = 8 , & R₂ = 32. Determine the current through R₁, R₂, and the current coming out of V. (Io). R₂ V₁ R₁ Io I₁ = 12 Vo 012 || || ||