In the circuit shown, C1=5 µF, C2=45 µF, C3=35 µF, C4=35 µF, and C5=15 µF. Find the equivalent capacitance of the block (C1, C2, C3, C4): Ceq1: µF. Find the total equivalent capacitance of this circuit: Ceq µF. Find the charge on capacitor C5: q5= µC. Find the voltage drop across capacitor C5: V5= V. C1 C3 C2 C4 + C5 90.0 V
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Q: 6.00 2.00 μF 90.0 V
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Q: equivalent capacitance of the circuit
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- Can you help me solve this simple circuit. I don't think I'm doing it rightTwo capacitors C, and C₂ are connected in series. a) Derive an expression for the equivalent capacitance C. b) Calculate the equivalent capacitance Ceq of two capacitors of values 2 µF and 4 μF in series. c) Write down the three capacitances C₁,C2 and Ceq in order of increasing capacitance.Please asap
- Find the following. (In the figure use C1 = 37.80 µF and C2 = 31.80 µF.) (a) the equivalent capacitance of the capacitors in the figure above µF(b) the charge on each capacitor on the right 37.80 µF capacitor µC on the left 37.80 µF capacitor µC on the 31.80 µF capacitor µC on the 6.00 µF capacitor µC (c) the potential difference across each capacitor on the right 37.80 µF capacitor V on the left 37.80 µF capacitor V on the 31.80 µF capacitor V on the 6.00 µF capacitor VA circuit has a 42.3 pF capacitor, a 59.6 pF capacitor and a 69.4 pF capacitor in parallel with each other. What is the equivalent capacitance (in pico-Farads) of these three capacitors?CA C, AV C3 C2 C5 In the circuit above C1=3nF, C2=7nF, C3=9nF, C4=12NF, C5=161F, the battery emf = 17V. Find the energy stored on C3., when al capacitors are fully charged. State your answer in nJ (nanoJoules) to the nearest nJ. In addition to entering your final numerical answer into the box, solve this problem in detail on paper. Make sure that you write your solution neatly, starting with the clear diagram and all variables on it.
- E11P1Three capacitors with capacitances C1 = 7.9 μF, C2 = 2.1 μF, and C3 = 5.3 μF are connected in a circuit as shown in the figure, with an applied potential of V. After the charges on the capacitors have reached their equilibrium values, the charge Q2 on the second capacitor is found to be 70. μC. a) What is the charge, Q1, on capacitor C1? b) What is the charge, Q3, on capacitor C3? c) How much voltage, V, was applied across the capacitors?You are given the below circuit to analyze and told that the circuit has been complete for a long time. What is the charge of capacitor C1? In the circuit, Rд=41 £2, RB=621 £2, Rc=110 £2, С₁=54 μF, C₂=22 μF, Vc3-6 V and V1=38.3 V. The charge on C₁ = V₁ ww RA w RB C1 C₂ C3 M Rc
- Four capacitors are arranged in the circuit shown in the figure. The capacitors have the values C1 = 26.5 µF, C2 = 45.5 µF, C3 = 50.5 µF, and C4 = 40.5 µF, and the power supply is at voltage V = 19.5 V. C, What is the equivalent capacitance of the circuit? V equivalent capacitance: 14.14 HF What is the charge on capacitor C2? charge on C2: 275.73 x10–6 C What is the potential difference across capacitor C3? 6.8 potential difference across C3: V Incorrect What is the potential energy stored in capacitor C4? 9.3 x106 potential energy stored in C4: J Incorrect 生A C1 +47 C2 B C3 C4 The circuit shown above has capacitors in a network. If C1 is 0.938 F, C2 is 0.329 F, C3 is 0.808 F, and C4 is 0.307 F, what the capacitance of the entire circuit (as measured between A and B)? Report your answer to three significant digits.The capacitors C₁ = 42.5 µF and C₂ = 127.5 µF are connected to a 9-V battery as shown in the figure below. What is the equivalent capacitance of the circuit? C₁ HH S €₂ V HI The equivalent capacitance, Ceq = What is the charge in each capacitor? The charge in C₁, Q₁ = Units UC The charge in C₂, Q₂ = What is the energy stored in each capacitor? The energy in C₁, U₁ : = The energy in C₂, U₂ = Units HC Units mJ Units mJ Units UF