In the figure, V = 18.0 V, C₁ = 25.0 µF, C₂ = 20.0 μF, C3= 15.0 µF and C4 = 10.0 μF. (a) What is the equivalent capacitance of this circuit? (b) What is the charge on capacitor 4? (c) What is the energy stored in capacitor 2? Include the reduced circuit diagrams for this situation. V F G₁₂₁ C₂ C3 C4
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- Consider the circuit shown in the figure, with C₁ = 2.42 μF and C₂ = 7.54 µF. 2 2.00 µF 6.00 µF + 90.0 V 1 C₂ (a) Find the equivalent capacitance (in µF) of the system. UF (b) Find the charge (in μC) on each capacitor. 2.42 μF capacitor UC 6.00 μF capacitor 7.54 µF capacitor 2.00 µF capacitor 오오오 (c) Find the potential difference (in V) on each capacitor. 2.42 μF capacitor V 6.00 μF capacitor V 7.54 µF capacitor V 2.00 uF capacitor V (d) Find the total energy (in m3) stored by the group. mJIn the circuit shown in Figure C₁ = 15.0μF, C₂ = 20.0μF, R₁ = 30.0Q2, R₂ = 50.0Q2. Both capacitors are initially charged to Vi = 45.0 V. a) Calculate the equivalent capacitance and the equivalent resistance. b) Calculate the charge accumulated on each capacitor. c) Calculate the time after closing the switch at which the potential across each capacitor will be reduced to V₁ = 10.0 V. S R₁ R₂ C₁- C₂ ‘TTHW #4
- Consider the circuit shown in the figure, with C₁ = 4.62 μF and C₂ = 7.44 μF. 2.00 µF 6.00 µF + 90.0 V C₂ (a) Find the equivalent capacitance (in µF) of the system. μF (b) Find the charge (in µC) on each capacitor. 4.62 μF capacitor 6.00 μF capacitor 7.44 μF capacitor 2.00 μF capacitor 9999 μC μC μC (c) Find the potential difference (in V) on each capacitor. 4.62 µF capacitor V 6.00 μF capacitor V 7.44 μF capacitor V 2.00 μF capacitor V (d) Find the total energy (in mJ) stored by the group. mJConsider the circuit shown below where four capacitors, C1=3.8 μF , C2=4.5 μF , C3=3.6 μF and C4=2.7 μF are connected to a battery of voltage V=21 V. Determine the charge on C1. Express your answer using one decimal place in units of μC.Consider the circuit shown in the figure, with C₁ = 6.92 µF and C₂ = 6.84 µF. 2.00 µF 6.00 µF + 90.0 V (a) Find the equivalent capacitance (in μF) μF (b) Find the charge (in µC) on each capacitor. 6.92 μF capacitor 6.00 μF capacitor 6.84 μF capacitor 2.00 μF capacitor mJ 9999 (c) Find the potential difference (in V) on each capacitor. 6.92 μF capacitor V 6.00 μF capacitor V 6.84 μF capacitor 2.00 μF capacitor the system. V (d) Find the total energy (in mJ) stored by the group.
- Consider the circuit shown in the figure, with C, , = 5.62 µF and C, = 7.44 µF. 6.00 µF 2.00 µF C2 + 90.0 V (a) Find the equivalent capacitance (in µF) of the system. (b) Find the charge (in µC) on each capacitor. 5.62 µF capacitor 6.00 µF capacitor 7.44 µF capacitor 2.00 µF capacitor HC (c) Find the potential difference (in V) on each capacitor. 5.62 µF capacitor V 6.00 µF capacitor V 7.44 µF capacitor V 2.00 µF capacitor V (d) Find the total energy (in mJ) stored by the group. m)Consider the circuit shown in the figure, with C₁ = 5.42 μF and C₂ = 7.84 μF. 2.00 μF 6.00 µF + 90.0 V C₂ (a) Find the equivalent capacitance (in µF) of the system. μF (b) Find the charge (in µC) on each capacitor. 5.42 μF capacitor 6.00 μF capacitor 7.84 μF capacitor 2.00 μF capacitor μC μC μC HC i (c) Find the potential difference (in V) on each capacitor. 5.42 μF capacitor V 6.00 μF capacitor V 7.84 μF capacitor 2.00 μF capacitor V (d) Find the total energy (in mJ) stored by the group. mJFor the capacitor network illustrated in the figure, the potential difference across ab is 12 V. a) The charge on the 8.60µF capacitor is:b) The charge on the 6.20µF capacitor is:c) The voltage across the 3.50 capacitor is:d) The equivalent capacitance of the circuit is:e) The capacitor that experiences the least voltage is that of:
- E11P1EMF = Vo = 6 volts. and C = 5 μF Calculate the theoretical value of the charge (q) in the capacitor during charging at t = RC. Use equation 3.You are given the below circuit to analyze and told that the circuit has been complete for a long time. What is the charge of capacitor C1? In the circuit, Rд=41 £2, RB=621 £2, Rc=110 £2, С₁=54 μF, C₂=22 μF, Vc3-6 V and V1=38.3 V. The charge on C₁ = V₁ ww RA w RB C1 C₂ C3 M Rc