Consider the accompanying data on breaking load (kg/25 mm width) for various fabrics in both an unabraded condition and an abraded condition. Use the paired t test to test Ho: Ho = 0 versus H: u, > 0 at significance level 0.01. (Use up = Hu - HA) Fabric 1 4 5 6 7 8 36.5 55.0 51.2 38.7 43.2 48.8 25.6 49.8 A 28.5 20.0 46.0 34.0 36.5 52.5 26.5 46.5 A USE SALT Calculate the test statistic and determine the P-value. (Round your test statistic to one decimal place and your P-value to three decimal places.) t = (No Response) 1.7 P-value = (o Response) 0.063 State the conclusion In the problem context. P Fail to reject Ho. The data does not suggest a significant mean difference in breaking load for the two fabric load conditions. O Fail to reject Ho. The data suggests a significant mean difference in breaking load for the two fabric load conditions. O Reject Hg. The data suggests a significant mean difference in breaking load for the two fabric load conditions. O Reject Ho. The data does not suggest a significant mean difference breaking load for the two fabric load conditions.
Consider the accompanying data on breaking load (kg/25 mm width) for various fabrics in both an unabraded condition and an abraded condition. Use the paired t test to test Ho: Ho = 0 versus H: u, > 0 at significance level 0.01. (Use up = Hu - HA) Fabric 1 4 5 6 7 8 36.5 55.0 51.2 38.7 43.2 48.8 25.6 49.8 A 28.5 20.0 46.0 34.0 36.5 52.5 26.5 46.5 A USE SALT Calculate the test statistic and determine the P-value. (Round your test statistic to one decimal place and your P-value to three decimal places.) t = (No Response) 1.7 P-value = (o Response) 0.063 State the conclusion In the problem context. P Fail to reject Ho. The data does not suggest a significant mean difference in breaking load for the two fabric load conditions. O Fail to reject Ho. The data suggests a significant mean difference in breaking load for the two fabric load conditions. O Reject Hg. The data suggests a significant mean difference in breaking load for the two fabric load conditions. O Reject Ho. The data does not suggest a significant mean difference breaking load for the two fabric load conditions.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![Consider the accompanying data on breaking load (kg/25 mm width) for various fabrics in both an unabraded condition and an abraded condition. Use the paired t test to test \( H_0: \, H_D = 0 \) versus \( H_a: \, H_D > 0 \) at significance level 0.01. (Use \( H_D = \mu_U - \mu_A \).)
\[
\begin{array}{c|cccccccc}
\text{Fabric} & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 \\
\hline
U & 36.5 & 55.0 & 51.2 & 38.7 & 43.2 & 48.8 & 25.6 & 49.8 \\
A & 28.5 & 20.0 & 46.0 & 34.0 & 36.5 & 52.5 & 26.5 & 46.5 \\
\end{array}
\]
Calculate the test statistic and determine the \( P \)-value. (Round your test statistic to one decimal place and your \( P \)-value to three decimal places.)
\[
t = \boxed{1.7}
\]
\[
P\text{-value} = \boxed{0.063}
\]
State the conclusion in the problem context.
- \(\textcolor{green}{\text{✓}}\) Fail to reject \( H_0 \). The data does not suggest a significant mean difference in breaking load for the two fabric load conditions.
- ☐ Fail to reject \( H_0 \). The data suggests a significant mean difference in breaking load for the two fabric load conditions.
- ☐ Reject \( H_0 \). The data suggests a significant mean difference in breaking load for the two fabric load conditions.
- ☐ Reject \( H_0 \). The data does not suggest a significant mean difference in breaking load for the two fabric load conditions.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffea4cb18-f853-4dd5-87f1-44780e7d8dd9%2F86bad312-bbe7-4375-833c-df9d2264ee6c%2Fhwpnnme_processed.png&w=3840&q=75)
Transcribed Image Text:Consider the accompanying data on breaking load (kg/25 mm width) for various fabrics in both an unabraded condition and an abraded condition. Use the paired t test to test \( H_0: \, H_D = 0 \) versus \( H_a: \, H_D > 0 \) at significance level 0.01. (Use \( H_D = \mu_U - \mu_A \).)
\[
\begin{array}{c|cccccccc}
\text{Fabric} & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 \\
\hline
U & 36.5 & 55.0 & 51.2 & 38.7 & 43.2 & 48.8 & 25.6 & 49.8 \\
A & 28.5 & 20.0 & 46.0 & 34.0 & 36.5 & 52.5 & 26.5 & 46.5 \\
\end{array}
\]
Calculate the test statistic and determine the \( P \)-value. (Round your test statistic to one decimal place and your \( P \)-value to three decimal places.)
\[
t = \boxed{1.7}
\]
\[
P\text{-value} = \boxed{0.063}
\]
State the conclusion in the problem context.
- \(\textcolor{green}{\text{✓}}\) Fail to reject \( H_0 \). The data does not suggest a significant mean difference in breaking load for the two fabric load conditions.
- ☐ Fail to reject \( H_0 \). The data suggests a significant mean difference in breaking load for the two fabric load conditions.
- ☐ Reject \( H_0 \). The data suggests a significant mean difference in breaking load for the two fabric load conditions.
- ☐ Reject \( H_0 \). The data does not suggest a significant mean difference in breaking load for the two fabric load conditions.
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