many people typically andom sample households reveals the statistics ē = 4 and s = 1.2 people per household Here, we should use: O 2-SampTInt

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### Understanding Household Occupancy Through Statistics

A government needs to know how many people typically occupy a household. If a random sample of 105 households reveals the statistics \( \bar{x} = 4 \) and \( s = 1.2 \) people per household, how should we proceed?

Given this data, we should use one of the following methods to determine a confidence interval or compare statistics:

- \( \bigcirc \) 2-SampTInt
- \( \bigcirc \) TInterval
- \( \bigcirc \) 2-SampZInt
- \( \bigcirc \) 1-PropZInt
- \( \bigcirc \) ZInterval
- \( \bigcirc \) 2-PropZInt

**Explanation:**
To determine the average number of people per household and understand the variability of this statistic, we need to calculate a confidence interval for the mean. Given the sample size (n = 105) and the sample statistics (\( \bar{x} = 4 \) and \( s = 1.2 \)), we will generally use a TInterval (confidence interval for the mean using a t-distribution). This is because we often use t-distributions for sample sizes below 30, but it is also commonly utilized as a more robust measure even for larger samples when the population standard deviation is unknown.

#### Answer:
- Select the **TInterval** method.

This method will help in estimating the population mean number of people per household with a certain level of confidence (typically 95% confidence).
Transcribed Image Text:### Understanding Household Occupancy Through Statistics A government needs to know how many people typically occupy a household. If a random sample of 105 households reveals the statistics \( \bar{x} = 4 \) and \( s = 1.2 \) people per household, how should we proceed? Given this data, we should use one of the following methods to determine a confidence interval or compare statistics: - \( \bigcirc \) 2-SampTInt - \( \bigcirc \) TInterval - \( \bigcirc \) 2-SampZInt - \( \bigcirc \) 1-PropZInt - \( \bigcirc \) ZInterval - \( \bigcirc \) 2-PropZInt **Explanation:** To determine the average number of people per household and understand the variability of this statistic, we need to calculate a confidence interval for the mean. Given the sample size (n = 105) and the sample statistics (\( \bar{x} = 4 \) and \( s = 1.2 \)), we will generally use a TInterval (confidence interval for the mean using a t-distribution). This is because we often use t-distributions for sample sizes below 30, but it is also commonly utilized as a more robust measure even for larger samples when the population standard deviation is unknown. #### Answer: - Select the **TInterval** method. This method will help in estimating the population mean number of people per household with a certain level of confidence (typically 95% confidence).
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