Data on pull-off force (pounds) for connectors used in an automobile engine application are as follows:79.6 75.1 78.2 74.1 73.9 75.0 77.6 77.3 73.8 74.6 75.5 74.0 74.775.9 72.7 73.8 74.2 78.1 75.4 76.3 75.3 76.2 74.9 78.0 75.1 76.8If necessary, round all intermediate calculations to four decimal places (e.g. 12.3456).(a) Calculate a point estimate of the mean pull-off force of all connectors in the population (Round the answer to four decimal places(e.g. 90.2353).)(b) Calculate a point estimate of the pull-off force value that separates the weakest 50% of the connectors in the population from thestrongest 50% (Express the answer to two decimal place (e.g. 90.15).)(c) Calculate the point estimate of the population variance (Round the answer to three decimal places (e.g. 3.567).)(d) Calculate the point estimate of the population standard deviation (Round the answer to two decimal places (e.g. 1.23).)(e) Calculate the standard error of the point estimate found in part (a) (Round the answer to two decimal places (e.g. 1.23).)(f) Calculate a point estimate of the proportion of all connectors in the population whose pull-off force is less than 73 pounds (Roundthe answer to three decimal places (e.g. 0.123).)

Since you have posted a question with multiple sub-parts, we will solve first three sub parts for…

Answered: 75.9 72.7 73.8 74.2 78.1 75.4 76.3 75.3…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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5 and 6. The following data was collected from 1 bag of Hershey Kisses®. Each Kiss® was weighed in grams with the wrapper and recorded in the table below. Hershey claims that there are 368 grams of chocolate in one bag. Hershey Kiss Weights in Grams 4.76 4.72 4.74 4.55 4.91 4.74 4.78 4.71 4.80 4.78 4.78 4.75 4.79 4.82 4.91 4.83 4.68 4.74 4.70 4.80 4.70 4.76 4.70 4.83 4.93 4.74 4.84 4.82 4.76 4.77 4.72 4.78 4.83 4.75 4.74 4.68 4.84 4.71 4.71 4.76 4.66 4.78 4.73 4.74 4.92 4.77 4.80 4.79 4.86 4.64 4.78 4.70 4.75 4.78 4.76 4.83 4.66 4.77 4.83 4.78 4.69 4.81 4.68 4.78 4.88 4.72 4.85 4.85 4.81 4.74 4.80 4.82 4.84 4.70 4.85 4.70 4.81 4.72 4.79 4.73 4.61 Based on Hershey's® claim for 368 total net grams of chocolate in the bag, approximately how many Kisses® too many or too few are there? Assume that the Kisses® were weighed with the wrapper, each wrapper weighs 0.12 grams, and the net grams listed on the bag are for the chocolate only. Give some possible…
Listed below are the measured radiation absorption rates (in W. 5-number summary. 1.12 0.52 0.51 0.92 0.7
(3-B is needed to answer it I am only asking for question 4.) 3) You go out and collect the following estimates of earthworms / acre:54,276 57,378 51,108 66,190 66,232 59,018 57,159These data yield the following: ̄y = 59,765.86, and s = 5,689.606a) Construct a 90% CI for these data.b) Construct a 99% CI for these data.c) Darwin once estimated that an acre of soil had about 50,000 worms in it. Is his estimateconsistent with the data above? (Historical note: His estimate was considered way too high inhis day). 4) Consider the results of 3(b). Notice that all the data fit within the 99% confidence interval. Is thisusually the case (in other words, will a 99% CI contain most of the observations)?Caution: a lot of people get this wrong! Here's a hint: suppose you had measured the worms in6000 acres (instead of just 7). What happens to the confidence interval? If you're not sure,substitute 6,000 for 7 in your calculation for (b) to see what happens.
A survey of the opinions of property owners about a street widening project was taken to determine whether the resulting opinion was related to the distance of front footage. A randomly selected sample of 100 property owners was contacted and the results are shown below. Opinion Front-Footage For Undecided Against Under 45 feet 12 4 4 45 – 120 feet 35 5 30 Over 120 feet 3 2 5 What is the computed value of chi-square? 5.4787 4.9985 9.2784 7.9842 11.0355
Given the data points, 8.12 8.08.8.05-8.16 8.11.8.17,8.14, calculate the Standard Error in the Mean. Select one: O a. 0.00196 Оь. 0.01289 O c. 0.04298 O d. 0.01625 Oa.
Listed below are the measured radiation absorption rates ( in 5 - number summary . W/kg) corresponding to 11 cell phones . Use the given data to construct a boxplot and identify the 1.49,1.25, 1.38, 1.04, 1.46, 1.31, 1.28, 0.73, 1.41, 0.58, 1.36

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