What can be a reasonable hypothesis from the following observed in vitro data?Compound 1Kd = 20 nMCompound 2K₁ = 35 mMThere is an important hydrophobic interaction at the binding region.There is not much space at the binding region, so removing the aromatic ring increases affinity.O The removed aromatic ring is not part of the pharmacophore.O The removed aromatic ring was getting metabolized and subsequently easily eliminated.O Changing the methoxy group for an electron withdrawing group will result in decrease of affinity.

Smaller the Kd (dissociation constant) greater the affinity of molecule on the active site of the…

Compound 1 Kd = 20 nM Compound 2 K= 35 mM O There is an important hydrophobic interaction at the binding region. O There is not much space at the binding region, so removing the aromatic ring increases affinity. The removed aromatic ring is not part of the pharmacophore. The removed aromatic ring was getting metabolized and subsequently easily eliminated. O Changing the methoxy group for an electron withdrawing group will result in decrease of affinity

Compound 1 Kd = 20 nM Compound 2 K= 35 mM O There is an important hydrophobic interaction at the binding region. O There is not much space at the binding region, so removing the aromatic ring increases affinity. The removed aromatic ring is not part of the pharmacophore. The removed aromatic ring was getting metabolized and subsequently easily eliminated. O Changing the methoxy group for an electron withdrawing group will result in decrease of affinity

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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