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into O RNA H Н Н Base Н ОН Н H -0-m OH Н Base Н ОН 1 5' ww Н Н O о Н н Base Н Н -o-m 0 3' Н Base Н ОН 2 5' ww H ܝܠ О НО Н Н H что-т 3' H Н H Base H Base ОН но- но 5' Н 3 Н Н ОН O н Н Base O-P=0 O O-P=0 O Н Т Base H O OH

into O RNA H Н Н Base Н ОН Н H -0-m OH Н Base Н ОН 1 5' ww Н Н O о Н н Base Н Н -o-m 0 3' Н Base Н ОН 2 5' ww H ܝܠ О НО Н Н H что-т 3' H Н H Base H Base ОН но- но 5' Н 3 Н Н ОН O н Н Base O-P=0 O O-P=0 O Н Т Base H O OH

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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1) What is the subject of each of the figures above ? 2) What is the main message of figure? 3) Give a brief but complete description of the three sections of the chemical mechanism along with a statement on the significance of the reaction.
5' H RNA Н 0-P=0 0- Н OH Base H H -o-m O 3' -ОН Н Н Base H ОН 1 5' wh Н Н 0-Р О H Base Н H Н Lo-m 3' Н Base H ОН 2 H 5' при НО 0- Н Н Н Н о О пр 3' О H Н O H Base Base OH Н H2O= 5' при но 5' 0. Н 3 Н H О Н O-P=0 Base OH O O-P=0 О Н Н Т Н Base Н OH
Transcribed Image Text:5' H RNA Н 0-P=0 0- Н OH Base H H -o-m O 3' -ОН Н Н Base H ОН 1 5' wh Н Н 0-Р О H Base Н H Н Lo-m 3' Н Base H ОН 2 H 5' при НО 0- Н Н Н Н о О пр 3' О H Н O H Base Base OH Н H2O= 5' при но 5' 0. Н 3 Н H О Н O-P=0 Base OH O O-P=0 О Н Н Т Н Base Н OH
Expert Solution
Step 1

The given structure contains pentose sugar, phosphate group and nitrogenous base. Hence, it is a nucleic acid.

There are two nucleic acids.

Deoxyribonucleic acid(DNA) which do not contain OH group at second carbon of the pentose ring.

Ribonucleic acid(RNA) which contains OH group at the second carbon of the pentose ring.

The pentose sugar of the given structures have OH group on second carbon. Hence, the nucleic acid is ribonucleic acid(RNA).

 

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