Complete the following ANOVA summary table for a two-factor fixed-effects ANOVA, where there are four levels of factor A (school) and seven levels of factor B (curriculum design). Each cell includes 15 students. Use a significance level of α = 0.05.\[\begin{array}{|c|c|c|c|c|c|}\hline\text{Source} & \text{SS} & \text{df} & \text{MS} & F & p \\\hlineA & 3247.5 & & & & \\A \times B & 5831.7 & & & & \\\text{Error} & 83496 & & & & \\\text{TOTAL} & 94121.2 & & & & \\\hline\end{array}\]**Decision for the main effect of factor A:**- Reject the null \(H_{0A}\)- Fail to reject the null \(H_{0A}\)**Decision for the main effect of factor B:**- Reject the null \(H_{0B}\)- Fail to reject the null \(H_{0B}\)**Decision for the interaction effect between factors A and B:**- Reject the null \(H_{0A \times B}\)- Fail to reject the null \(H_{0A \times B}\)**How would you summarize the results of this ANOVA?**- One main effect only- Two main effects only- One main effect with no interaction- One main effect with an interaction- Two main effects with an interaction- Only an interaction effect- No significant effects

The sum of squared for factor A is, SSA=TSS-SSB-SSAB-SSE=94,112.1-3,247.5-5,831.7-83,496=1,536.9…

Complete the following ANOVA summary table for a two-lactor fixed ellects ANOVA, where there are four levels of factor A(school) and seven levels of factor B (curriculum designil. Each cell indudes 15 studenes. Use a significance level of e 0.0s. Source SS MS B 3247.5 Ax B 5831.7 Error 83496 TOTAL 94112.1 Decision for the main ellect of lacior A Oreject the nul Hu Olail to reject the null Hạ, Decision for the main eflect of factor D Oreject the nul Hes Olail to reject the nullH, Decision for the interaction elfect beween factors Aand D Oreject the nul H Olail to reject the null Has How would you summarize the results of this ANOVA Oone main eflect only Otwo main ellects vith no interaction

Complete the following ANOVA summary table for a two-lactor fixed ellects ANOVA, where there are four levels of factor A(school) and seven levels of factor B (curriculum designil. Each cell indudes 15 studenes. Use a significance level of e 0.0s. Source SS MS B 3247.5 Ax B 5831.7 Error 83496 TOTAL 94112.1 Decision for the main ellect of lacior A Oreject the nul Hu Olail to reject the null Hạ, Decision for the main eflect of factor D Oreject the nul Hes Olail to reject the nullH, Decision for the interaction elfect beween factors Aand D Oreject the nul H Olail to reject the null Has How would you summarize the results of this ANOVA Oone main eflect only Otwo main ellects vith no interaction

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

You decided to conduct Bonferroni post hoc analyses in MS Excel. Inspect the MS Excel output and answer these questions. a) Were these poc học analyses conducted assuming equal variances? b) What is the directionality for each comparison? c) What is the new alpha level that you need to use to determine significance? d) What conclusions can you make regarding birth order and Peabody Picture Vocabulary Test scores for these Grade 2 students? Oldest Child Middle Child Oldest Child Youngest Child Middle Child Youngest Child Mean 94.75 68.375 Mean 94.75 95 Mean 68.375 95 Variance 60.21428571 41.98214286 Variance 60.21428571 127.5 Variance 41.98214286 127.5 Observations 8. Observations 8 Observations 8 Pooled Variance 51.09821429 Pooled Variance 96.1 Pooled Variance 87.59166667 Hypothesized Mean Difference Hypothesized Mean Difference Hypothesized Mean Difference df 14 df 15 df 15 t Stat P(T<=t) one-tail t Critical one-tail t Stat P(T<=t) one-tail 7.37937537 t Stat -0.052483175 -5.854637484…
Is there a difference in the average number of bedrooms in houses with pools as compared to houses without pools? Use alpha = 0.05. First attached image is the anova calculations with houses with no pools, second image is houses with pools. Looking for clarification on how it is compared
The leader of two postpartum women’s support groups is interested in the depression levels of the women in her groups. She administers the Center for Epidemiologic Studies Depression Scale (CES-D) screening test to the members of her groups. The CES-D is a 20-question self-test that measures depressive feelings and behaviors during the previous week. The mean depression level from the screening test for the 10 women in the first group is μ₁ = 16; the mean depression level for the 14 women in the second group is μ₂ = 10. Without calculating the weighted mean for the combined group, you know that the weighted mean is:
For the Kruskal-Wallis ANOVA: Is there a statistical difference between the rankings of the core temperatures of the groups exposed to either a cold, neutral, or hot environment? (smaller number= coldest core temperature ranking, largest number= hottest core temperature ranking).” Ranks that are tied, get an average value of the two ranks. The Data is attached. Thank you.
A research assigns 21 adolescents to rate the likability of a person described in a vignette in hqvinf one of three personality traits. An equal number of participents are assigned to each group. If Fobt = 4.08 for this study, then what was the decision at a .05 level of significance for a one-way between subjects ANOVA? df bg= df E= F crit=
Need help with a
Please show with complete solution. Do not use excel please
Compute a one-way ANOVA on the following data using 0.05 significance level. Group A Group B Group C 14 11 14 13 12 12 10 13 13 12 13 12 14 ANOVA Source of Variation SS df MS F P-value F crit Between Groups ? ? ? ? ? Within Groups ? ? ? Total ? ?
Answer all of the following question, anova table have given
Which two fields of the ANOVA summary table help us find the critical value? Select all that apply A.df between B.MS within C.df within D. MS between