A data set includes the counts of chocolate chips from three different types of Chips Ahoy cookies. The accompanying StatCrunch display shows results from analysis of variance used with those three types of cookies. Use a 0.05 significance level to test the claim that thethree different types of cookies have the same mean number of chocolate chips.ANOVA tableSourceDFMSF-StatP-valueColumnsErrorTotal2 1012.7500 506.37500 59.1368 <0.000177 659.33333 8.562770579 1672.0833Determine the null hypothesis.Họ:Determine the alternative hypothesis.Determine the test statistic.The test statistic is(Round to two decimal places as needed.)Determine the P-value.The P-value is(Round to three decimal places as needed.)What can you conclude?chocolate chip cookies haveV mean number of chocolate chips.ThereV sufficient evidence at a 0.05 significance level to warrant rejection of the claim that the three different types

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Answered: A data set includes the counts of…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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https://egcc.instructure.com/courses/12156/assignments/259149 Statistics students in Oxnard College sampled 9 textbooks in the Condor bookstore and recorded the number of pages in each textbook and its cost. The bivariate data are shown below: Number of Pages (r) Cost(y) 313 49.04 836 80.88 nces 762 66.96 221 26.68 ations 325 47 965 92.2 డెడితితలో Drive 312 41.96 22.84 57.12 65 223 589 Course ions A student calculates a linear model (Please show your answers to two decimal places) Use the model to estimate the cost when number of pages is 430. Cost = $ (Please show your answer to 2 decimal places.) Submit Question e to search
The average retirement age in America is 65 years old. Do small business owners retire at an older average age? The data below shows the results of a survey of small business owners who have recently retired. Assume that the distribution of the population is normal. 71, 61, 60, 60, 71, 62, 66, 70, 71, 63, 63, 58 What can be concluded at the the αα = 0.05 level of significance level of significance? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion The null and alternative hypotheses would be: H0:H0: ? μ p Select an answer > < = ≠ H1:H1: ? p μ Select an answer < > = ≠ The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? ≤ > αα Based on this, we should Select an answer fail to reject accept reject the null hypothesis. Thus, the final conclusion is that ... The data suggest the…
Report summary statistics for the two variables ‘Run_Pulse’ and ‘Rest_Pulse’ in the table below: Sample Size Minimum Maximum Mean Median Standard Deviation Standard Error Run_Pulse Rest_Pulse
For the Kruskal-Wallis ANOVA: Is there a statistical difference between the rankings of the core temperatures of the groups exposed to either a cold, neutral, or hot environment? (smaller number= coldest core temperature ranking, largest number= hottest core temperature ranking).” Ranks that are tied, get an average value of the two ranks. The Data is attached. Thank you.
An engineer designed a valve that will regulate water pressure on an automobile engine. The engineer designed the valve such that it would produce a mean pressure of 7.4 pounds/square inch. It is believed that the valve performs above the specifications. The valve was tested on 280 engines and the mean pressure was 7.5 pounds/square inch. Assume the variance is known to be 0.81. A level of significance of 0.05 will be used. Make a decision to reject or fail to reject the null hypothesis. Make a decision. Answer O Reject Null Hypothesis O Fail to Reject Null Hypothesis Tables: Keypad Keyboard Shortcut
Use the 1odwing Wildlife: Coyotes A random sample of 46 adult coyotes in a region of northern Minnesota showed the average age to be z = 2.05 years, with sample standard deviation 8 = 0.82 years (based on information from the book Coyotes: Biology, Behavior and Management by M. Bekoff, Academic Press). However, it is thought that the overall population mean age of coyotes is µ=1.75. Do the sample data indicate that coyotes in this region of northern Minnesota tend to live longer than the average of 1.75 years? Use a = 0.01. Fl in the blanks a 007 • Ho u- 175 years * H u> 176 yean QUESTION 7 What is your test statistic? (t-statistic) 2.48 QUESTION 8 What is your p-value? (Hint You will need the degrees of freedom to find the p-value.) <0.01d QUESTION 9 Do you reject the null hypothesis? O Yes No
On average, ages of people in a sample deviate from the mean by 3.23 years. Find the variance. Do not round your answe Submit Question Online ver Proctor om MacBook Pro G Search or type URL 6
Another idea is to look at how a team's payroll impacts its home attendance. Higher payroll usually signals more higher-skilled players on a roster which should brings fans to the ballpark to see these players. Create 2 samples based on Team Salary and calculate average attendance, variance of attendance, and standard deviation of attendance for each sample. Sample 1 = 10 teams with the highest team salary Sample 2 = 10 teams with the lowest team salary Tip: Use Excel's sorting tool to sort the data by salary (highest to lowest), and copy the 10 highest and 10 lowest into a separate part of the spreadsheet for easier analysis. Sample 1 Sample 2 Top 10 Team Salary Bottom 10 Team Salary Sample mean attendance mil mil Sample attendance variance mil mil Sample attendance standard deviation mil mil Perform a hypothesis test to determine whether there is a difference in the mean attendance of teams between the two groups…
A researcher is studying hospitals cleanliness comparing carpeted rooms with uncarpted rooms. This researcher would like to determine if the mean number of airborne bacteria (per cubic foot) in carpeted rooms differs from the mean amount of airborne bacteria in uncarpeted rooms. To test thus, carpeted and uncarpeted hospitals rooms were randomely selected. Then air from the room was pumped over a petri dish and the number of bacteria of the patri dish was recorded. Since both samples are small (less than 30), you may assume that number of bacteria per petri dish is normally distributed. Using significant level =.05, use the unequal varance t-test for means to determine if the mean number of airborne bacteria in carpeted rooms differs from the mean number of airborne bacteria in uncarpeted rooms. Follow all steps and remember that you must assign population 1 and population 2 before you set up your Ho and Ha.
In a test of weight loss programs, 111 subjects were divided such that 37 subjects followed each of 3 diets. Each was weighed a year after starting the diet and the results are in the ANOVA table below. Use a 0.05 significance level to test the claim that the mean weight loss is the same for the different diets. Source of Variation Between Groups Within Groups Total P-value 25.38918 0.8127 0.446353 F crit 3.080387 df MS F 50.778 3373.977 3424.755 2 108 31.24053 110 Should the null hypothesis that all the diets have the same mean weight loss be rejected? O A. Yes, because the P-value is greater than the significance level. O B. No, because the P-value is greater than the significance level. OC. No, because the P-value is less than the significance level. O D. Yes, because the P-value is less than the significance level.
An Allied Health instructor at IVC was interested in comparing systolic blood pressure for vegetarian and nonvegetarian faculty and staff at IVC. Independent simple random samples of 85 vegetarians and 75 nonvegetarians resulted were collected. The summary statistics are presented in the table below. Is there compelling statistical evidence that the mean systolic blood pressure for vegetarians is lower than the mean systolic blood pressure for nonvegetarians? Use a significance value of 0.05. Two-Sample T-Test Standard Deviation Sample Mean Vegetarian Non- Vegetarian 85 124 39 75 139 40 Null Hypothesis, HO レ Alternative Hypothesis, H1 Test Statistic, t P-value く Significance level く Conclusion
The average retirement age in America is 62 years old. Do small business owners retire at a different average age? The data below shows the results of a survey of small business owners who have recently retired. Assume that the distribution of the population is normal. 69, 62, 73, 55, 74, 56, 60, 65, 75, 59, 66, 57, 61, 68 What can be concluded at the the αα = 0.01 level of significance level of significance? For this study, we should use Correct The null and alternative hypotheses would be: H0:H0: Correct Correct Correct H1:H1: Correct Correct Correct The test statistic Correct = Incorrect (please show your answer to 3 decimal places.) The p-value = Incorrect (Please show your answer to 4 decimal places.) The p-value is Correct αα Based on this, we should Correct the null hypothesis. Thus, the final conclusion is that ... The data suggest the populaton mean is significantly different from 62 at…

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