Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained: Volume of bucket = 9.3 Liters Mass of empty bucket = 9 kg Mass of bucket filled with dry- rodded coarse aggregate: Trial 1 = 30.25 kg Trial 2 = 29.76 kg Trial 3 = 31.12 kg a. Calculate the individual dry-rodded unit weight for each trial and the average dry-rodded unit weight of all trials. b. If the bulk dry specific gravity of the aggregate is 2.65, calculate the percent voids between aggregates particles for each trial and the average percent voids of all trials.
Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained: Volume of bucket = 9.3 Liters Mass of empty bucket = 9 kg Mass of bucket filled with dry- rodded coarse aggregate: Trial 1 = 30.25 kg Trial 2 = 29.76 kg Trial 3 = 31.12 kg a. Calculate the individual dry-rodded unit weight for each trial and the average dry-rodded unit weight of all trials. b. If the bulk dry specific gravity of the aggregate is 2.65, calculate the percent voids between aggregates particles for each trial and the average percent voids of all trials.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
![Coarse aggregate is placed in a rigid
bucket and rodded with a tamping rod
to determine its unit weight. The
following data are obtained:
Volume of bucket = 9.3 Liters
Mass of empty bucket = 9 kg
Mass of bucket filled with dry-
%3D
rodded coarse aggregate:
Trial 1 = 30.25 kg
Trial 2 = 29.76 kg
Trial 3 = 31.12 kg
a. Calculate the individual dry-rodded
unit weight for each trial and the
average dry-rodded unit weight of all
trials.
b. If the bulk dry specific gravity of the
aggregate is 2.65, calculate the percent
voids between aggregates particles for
each trial and the average percent voids
of all trials.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa197b116-9e74-4c3e-967c-6baf00236ede%2Fd8d9bdff-5307-443b-a2d2-a6ade8e2866e%2Fiemjck7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Coarse aggregate is placed in a rigid
bucket and rodded with a tamping rod
to determine its unit weight. The
following data are obtained:
Volume of bucket = 9.3 Liters
Mass of empty bucket = 9 kg
Mass of bucket filled with dry-
%3D
rodded coarse aggregate:
Trial 1 = 30.25 kg
Trial 2 = 29.76 kg
Trial 3 = 31.12 kg
a. Calculate the individual dry-rodded
unit weight for each trial and the
average dry-rodded unit weight of all
trials.
b. If the bulk dry specific gravity of the
aggregate is 2.65, calculate the percent
voids between aggregates particles for
each trial and the average percent voids
of all trials.
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