Sieve analysis test for fine aggregates was performed on a sample of fine aggregates and produced the following results: a. Calculate the percent passing through each sieve. b. Plot the percent finer in a semi-log gradation chart. c. What is the maximum aggregate size of the sample? d. What is the nominal maximum aggregate size of the sample? e. What is the fineness modulus? Is it in typical range? Sieve Size, 9.5 4.75 3.35 2.36 2.00 1.18 0.85 0.60 0.425 0.30 0.25 0.18 0.15 (No. 0.075 Pan mm (in) (3/8) (No. 4)|(No. 6) (No. 8)|(No. 10) (No. 16) (No. 20) (No. 30) (No. 40) (No. 50) (No. 60)|(No. 80) 100) |(No. 200) Amount 25 59 75 86 115 136 169 192 225 198 173 112 90 33 12 Retained, g

Sieve analysis test for fine aggregates was performed on a sample of fine aggregates and produced the following results: a. Calculate the percent passing through each sieve. b. Plot the percent finer in a semi-log gradation chart. c. What is the maximum aggregate size of the sample? d. What is the nominal maximum aggregate size of the sample? e. What is the fineness modulus? Is it in typical range? Sieve Size, 9.5 4.75 3.35 2.36 2.00 1.18 0.85 0.60 0.425 0.30 0.25 0.18 0.15 (No. 0.075 Pan mm (in) (3/8) (No. 4)|(No. 6) (No. 8)|(No. 10) (No. 16) (No. 20) (No. 30) (No. 40) (No. 50) (No. 60)|(No. 80) 100) |(No. 200) Amount 25 59 75 86 115 136 169 192 225 198 173 112 90 33 12 Retained, g

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: A 12.80 lb sample of quartzite was found to have the following amounts of material retained on each…

Q: Sieve Analysis of Fine Aggregates) Students have gathered data for sieve analysis of the following…

Q: Below is a sieve analysis for a fine aggregate. a. Complete the sieve analysis to get percent…

Q: Coarse aggregate placed igid buc its unit weight. The following data were obtained: Volume of bucket…

A: According to given data Coarse aggregate is placed in a rigid bucket (mold) and rodded with a…

Q: Based on the data in Table P9.32, determine the design binder content for aSuperpave mix design for…

A: Pavement design: In-pavement there two types of pavements are there, one is Rigid pavement and the…

Q: Table below shows the result of sieve analysis test on a sample of fine aggregate. What is the…

A: The Fineness Modulus (FM) of an aggregate is given by the sum of the cumulative percent retained on…

Q: 3. Coarse aggregate is placed in a rigid bucket and compacted with a tamping rod to determine its…

A: Coarse aggregates : Coarse aggregates are any particles larger than 0.19 inches in diameter, but…

Q: TEST PROCEDURE: 1. Dry the aggregate test sample to a constant weight at a temperature of 110 ±…

A: Note: Hi! Thank you for the question, As per the honour code, we are allowed to answer three…

Q: The sieve analysis results of an aggregate sample are provided below. What are the maximum…

A: Sieve size (mm)Mass retained (gms)9.504.7530.22.3675.41.18100.50.61350.31730.15121.90.07554Pan10To…

Q: 2. Three samples of aggregates are sieved to obtain the grading curve. A set of different sieves is…

A: Three samples of aggregates are given:-Sieve sizeMass of sieve (g)Mass of sieve+aggregates…

Q: For a fine aggregate, the value of fineness modulus was calculated to be 2.30. Is the particle size…

A: Fineness modulus indicates how coarse or fine an aggregate is. Higher the fineness modulus coarser…

Q: A sample of wet aggregate weighed 297.2 N. After drying in an oven, this sample weighed 281.5 N. The…

Q: Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit…

A: Given that, The volume of rigid bucket= 0.2 ft3 Weight of empty bucket= 18.2 lb Weight of…

Q: Q.2) Answer the following question. 1- The sieve analysis below was done for which type of…

A: The values given in the table is not correctly calculated. Correct values with table is given below.

Q: A sample of coarse aggregate is placed in a bucket of know volume (0.5 ft^3) and rodded with a…

A: Volume of bucket = 0.5 ft3Empty weight of the bucket = 20.3 lb

Q: Three samples of fine aggregate have the properties shown below. Determine in percentage: (a) total…

A: MeasureSampleABCWet Mass (g)521.0522.4523.4Dry Mass (g)491.6491.7492.1Absorption…

Q: Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit…

A: According to given data Coarse aggregate is placed in a rigid bucket (mold) and rodded with a…

Question

Sieve analysis test for fine aggregates was performed on a sample of fine aggregates and
produced the following results:
a. Calculate the percent passing through each sieve.
b. Plot the percent finer in a semi-log gradation chart.
c. What is the maximum aggregate size of the sample?
d. What is the nominal maximum aggregate size of the sample?
e. What is the fineness modulus? Is it in typical range?
Sieve Size,
9.5
4.75
3.35
2.36
2.00
1.18
0.85
0.60
0.425
0.30
0.25
0.18 0.15 (No.
0.075
Pan
mm (in)
(3/8) (No. 4)(No. 6) (No. 8) (No. 10) (No. 16) (No. 20)|(No. 30) (No. 40)|(No. 50)|(No. 60) (No. 80)
100)
|(No. 200)
Amount
25
59
75
86
115
136
169
192
225
198
173
112
90
33
12
Retained, g

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

The table below presents the results of the sieve analysis conducted on a sample of aggregate. Given the bulk specific gravities of 2.65 for coarse aggregate, 2.69 for fine aggregate, and 2.73 for filler, determine the bulk density of the aggregate sample. Additionally, calculate the maximum aggregate size and nominal aggregate maximum size. Sieve size (mm) 37.5 % Passing 100 Specification limit 25 92 100 90-100 19 83 76-90 12.5 9.5 4.75 2.36 0.3 71 62 53 32 15 56-80 48-74 29-59 19-45 5-17 0.075 4 2-8
Analysis of Fine AggregatesFill in the table:
46.5 kg of fine aggregate is mixed with 72.3 kg of coarse aggregate. The fine aggregate has a moisture content of 2.0% and absorption of 3.4%, whereas the coarse aggregate has a moisture content of 1.3% and absorption of 3.8%. What is the amount of water required to increase the moisture contents of both fine and coarse aggregates to reach absorption? Why is it important to determine the amount of water required to increase the moisture content of aggregate to reach absorption?
Table shows the grain size distributions of aggregates A, and B. Answer the following questions and show all calculations: What are the maximum sizes of aggregates A and B?
1 - show complete solution
5.14 Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained: Volume of bucket = ¹/2 ft³ Weight of empty bucket = 20.3 lb Weight of bucket filled with dry rodded coarse aggregate: Trial 176.6 lb Trial 275.1 lb Questions and Problems 217 Trial 3 78.8 lb a. Calculate the average dry-rodded unit weight b. If the bulk dry specific gravity of the aggregate is 2.620, calculate the percent voids between aggregate particles for each trial.
Referring to the aggregate gradations A, B, and C in Figure P5.26, answer the following questions: a. What is the maximum size of each gradation? b. What is the nominal maximum size of each gradation? c. Classify each gradation as dense, open, or gap indicating the reason for each classification. 100 A 80- 60 40 0.075 0.30 1.18 2.36 4.75 9.5 12.5 19.0 25.0 0.15 0.60 Sieve sizes (mm) FIGURE P5.26 Percent passing 20
Coarse aggregate is placed in a rigid bucket and compacted with a tamping rod to determineits unit weight. The following data are obtained:• Volume of bucket = 0.5 ft3• Weight of empty bucket = 20.3 lb• Weight of bucket filled with dry compacted coarse aggregate = 76.8 lba) Calculate the dry-compacted unit weight of the aggregate.b) If the bulk dry specific gravity of the aggregate is 2.620, calculate the percent voids.
Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained: Volume of bucket =14L Weight of empty bucket = 9.21kg Weight of bucket filled with dry rodded coarse aggregate: Trial 1 =34,75 kg Trial 2 =34.06 kg Trial 3 =35.74 kg a. Calculate the average dry-rodded unit weight b.If the bulk dry specific gravity of the aggregate is 2.620, calculate the percent voids between aggregate particles for each trial.
Void Content—Calculate the void content in the aggregate using the bulk densitydetermined by either the rodding, jigging or shoveling procedure, as follows:
Sieve analysis of a sample of fine aggregate resulted in the following data No. Sieve number 4 8 16 30 50 100 Sieve opening (mm) 4.75 2.36 1.18 0.6 0.3 0.15 Weight retained (g) 13 75 120 126 105 61 A) The total weight of the sample, assuming no mass loss during the analysis, is______ (g) a) 505; b) 500; c) 550 B) The half sieve used in the experiment is________. a) No.8; b) No.50; c) none of the above C) The fineness modulus of the aggregate________. a) 6.13; b) 3.16; c) 1.36 D) The average size of the aggregate___________. a) No.30; b) No.4; c) No.16
Distinguish porosity from voids content for aggregate with the help of schematic diagrams.