3. Coarse aggregate is placed in a rigid bucket and compacted with a tamping rod to determine its unit weight. The following data are obtained: • Volume of bucket = 0.5 ft3 • Weight of empty bucket = 20.3 lb • Weight of bucket filled with dry compacted coarse aggregate = 76.8 lb a) Calculate the dry-compacted unit weight of the aggregate. b) If the bulk dry specific gravity of the aggregate is 2.620, calculate the percent voids.

Q: Coarse aggregate placed igid buc its unit weight. The following data were obtained: Volume of bucket…

A: According to given data  Coarse aggregate is placed in a rigid bucket (mold) and rodded with a…

Q: bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained:…

A: V=0.3 ft3

Q: Calculate the percent voids between aggregate particles that have been compacted by rodding, if the…

A: Given that, Dry rodded unit weight of aggregate :  γb=1161 kg/m3 ⇒72.5 lb/ft3 Bulk dry specific…

Q: The sieve analysis results of an aggregate sample are provided below. What are the maximum…

A: Sieve size (mm)Mass retained (gms)9.504.7530.22.3675.41.18100.50.61350.31730.15121.90.07554Pan10To…

Q: 2. Three samples of aggregates are sieved to obtain the grading curve. A set of different sieves is…

A: Three samples of aggregates are given:-Sieve sizeMass of sieve (g)Mass of sieve+aggregates…

Q: Calculate the percent voids between aggregate particles that have been com-pacted by rodding, if the…

A: Given:  Dry unit weight yd = 1161 kg/m3 Specific gravity G = 2.639 To find: Percentage voids e = ?…

Q: A sample of wet aggregate weighed 297.2 N. After drying in an oven, this sample weighed 281.5 N. The…

A:

Q: Volume of measure, (ft³) Weight of measure (lb) Weight of measure + aggrega

A:

Q: Calculate the percent voids between aggregate particles that have been com- pacted by rodding, if…

A:

Q: Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit…

A: Given that,   The volume of rigid bucket= 0.2 ft3      Weight of empty bucket= 18.2 lb  Weight of…

Q: Q.2) Answer the following question. 1- The sieve analysis below was done for which type of…

A: The values given in the table is not correctly calculated. Correct values with table is given below.

Q: TABLE P5.21 Sieve Size, mm 25 19 12.5 9.5 4.75 2.36 Amount Retained, g 0 376.7 888.4 506.2 1038.4…

A: Sieve Analysis : To assess the grain size distribution of soils with a diameter higher than 0.075…

Q: A sample of coarse aggregate is placed in a bucket of know volume (0.5 ft^3) and rodded with a…

A: Volume of bucket = 0.5 ft3Empty weight of the bucket = 20.3 lb

Q: Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit…

A: According to given data  Coarse aggregate is placed in a rigid bucket (mold) and rodded with a…

Q: Samples of coarse aggregate from a stockpileare brought to the laboratory for determination of…

A:

Unit Conversion

Standard units are also called SI units. SI units are used for measuring a physical quantity satisfying certain conditions. There are two types of units: fundamental units and derived units. Fundamental units are physical quantities that are independent, that is, they do not depend on other quantities like mass, length, or time. There are plenty of quantities in our lives which need to be measured and compared. Measuring is the comparison of a particular physical quantity with its reference value. A unit is a measure of a fixed physical quantity. A physical quantity is the product of a unit and the numerical value we need to compare with.