rodded coarse aggregate: Trial 1 =34,75 kg Trial 2 =34.06 kg Trial 3 =35.74 kg a. Calculate the average dry-rodded unit weight b.If the bulk dry specific gravity of the aggregate is 2.620, calculate the percent voids between aggregate particles for each trial.

Q: A sieve analysis test was conducted for sample of fine aggregate and obtained the results as shown…

A: Given  Sieve Analysis results table . It is used to find fineness modulus of sand and percentage of…

Q: Based on the data in Table P9.32, determine the design binder content for aSuperpave mix design for…

A: Pavement design: In-pavement there two types of pavements are there, one is Rigid pavement and the…

Q: 1. Why do you think there is a need to agitate the aggregates inside the cylinder mold by rodding?

A: tests are done on aggregate so we can have information whether they are fit for use or not .  Note…

Q: Table below shows the result of sieve analysis test on a sample of fine aggregate. What is the…

A: The Fineness Modulus (FM) of an aggregate is given by the sum of the cumulative percent retained on…

Q: 1. Three samples of aggregates are sieved to obtain the grading curve. A set of different sieves is…

A: Note : Since you have asked multiple questions, we will solve the first question for you. If you…

Q: Sieve analysis test for fine aggregates was performed on a sample of fine aggregates and produced…

A:

Q: 3. Coarse aggregate is placed in a rigid bucket and compacted with a tamping rod to determine its…

A: Coarse aggregates : Coarse aggregates are any particles larger than 0.19 inches in diameter, but…

Q: bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained:…

A: V=0.3 ft3

Q: TEST PROCEDURE: 1. Dry the aggregate test sample to a constant weight at a temperature of 110 ±…

A: Note: Hi! Thank you for the question, As per the honour code, we are allowed to answer three…

Q: Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit…

A: Volume of bucket =14L=0.494 ft3weight of bucket= 9.21kg=20.20 lbweight of bucket filled with dry…

Q: The sieve analysis results of an aggregate sample are provided below. What are the maximum…

A: Sieve size (mm)Mass retained (gms)9.504.7530.22.3675.41.18100.50.61350.31730.15121.90.07554Pan10To…

Q: 2. Three samples of aggregates are sieved to obtain the grading curve. A set of different sieves is…

A: Three samples of aggregates are given:-Sieve sizeMass of sieve (g)Mass of sieve+aggregates…

Q: Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit…

A:

Q: A sample of wet aggregate weighed 297.2 N. After drying in an oven, this sample weighed 281.5 N. The…

A:

Q: The fineness modulus is a relative measure of how coarse or how fine an aggregate sample is.…

A: The fineness modulus is a value that signifies the average value of particle size.

Q: Calculate the fineness modulus. Express your final answer in 2 decimal places.

A: fineness modulus=(sum of cumulative percentage weight retained )/100

Q: Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit…

A: Given that,   The volume of rigid bucket= 0.2 ft3      Weight of empty bucket= 18.2 lb  Weight of…

Q: Please help.

A: (2) A pycnometer is a flask or container in which fine aggregates may be readily introduced. hence…

Q: Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit…

A: According to given data  Coarse aggregate is placed in a rigid bucket (mold) and rodded with a…

Q: 27 Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit…

A:

Q: Sieve analysis test for fine aggregates was performed on a sample of fine aggregates and produced…

A: Given, Sieve analysis diagram

Q: Given the bulk specific gravities of 2.65 for coarse aggregate, 2.69 for fine aggregate, and 2.73…

A:

Q: The following table shows the results obtained from laboratory tests done on samples of aggregates.…

A:

Q: choose true or false  If you know that weights of coarse aggregate as follow :Weight of aggregate…

A: Given data : A= Weight of aggregate stock = 5350 gm, B= weight of aggregate in oven dry= 5200 gm, C=…

Q: From a Fine Aggregate sample, the ff data are given below to determine only the SPECIFIC GRAVITIES…

A: Given data  MASS of oven dried aggregate (W1)=428.3g MASS of PYC filled with water (W2)=652.5g MASS…

Q: A saturated aggregate sample with an absolute volume of 5.05x10^-5 m^3 has a mass of 178 g before…

A: Given Absolute Volume V = 5.05 × 10-5 m3  Bulk Mass or Saturated Mass M = 178g Dry Mass Md = 139g…

Q: Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit…

A:

Q: Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit…

A:

Q: Table shows the grain size distributions of aggregates A, and B. Answer the following questions and…

A: Given: The grain size distributions of aggregates are shown below,

Q: Sieve analysis for fine and coarse aggregate is done, how can we say that those samples are good and…

A: The fineness modulus is the total of the cumulative percentage that stayed on the each sieve from…

Q: Referring to the aggregate gradations A, B, and C in Figure , answer the following questions:a. What…

A: Consider the figure of aggregate gradations.

Q: Sieve analysis test for fine aggregates was performed on a sample of fine aggregates and produced…

A: a). percent passing  Sieve Size(mm) Weight Retained Percentage Retained Cumulative Retained…

Q: 5.14 Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its…

A: Unit weight is defined as the ratio of total weight and the total volume of the material. The %…

Q: Referring to the aggregate gradations A, B, and C in Figure P5.26, answer the following questions:…

A: Given values: Consider the graph given.   Maximum size of aggregate is the smallest size of sieve…

Q: Coarse aggregate is placed in a rigid bucket and compacted with a tamping rod to determine its unit…

A: Given: The volume of the bucket =0.5 ft3. Weight of empty bucket = 20.3 lb. Weight of bucket filled…

Q: Calibration: 1. Mass of the measure plus plate, kg (Mm+p) 11.69 kg 15.47 kg 2. Mass of the measure…

A:

Soil Compaction Test

Soil compaction is the major area of geotechnical engineering. Soil is composed of multiple pores present on its surface, while the soil is mainly composed of gravel, sand, rocks, etc. The arrangement of these rocks and gravels is such that they build up voids (spaces) between them, which allows spaces for the roots of the plants and crops to spread and absorb the required amount of nutrients. Soil compaction is a major problem primarily caused by human activities, micro-organisms, and other multiple factors.