Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained: Volume of bucket = 1½ ft³ Weight of empty bucket Weight of bucket filled with dry rodded coarse aggregate 20.3 lb %3D Trial 1 = 69.6 lb Trial 2 = 68.2 lb Trial 3 = 71.6 lb a. Calculate the average dry-rodded unit weight b. If the bulk dry specific gravity of the aggregate is 2.620, calculate the per- cent voids between aggregate particles for each trial.

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Q: Sieve analysis test for fine aggregates was performed on a sample of fine aggregates and produced…

A:

Q: While measuring the abrasion value of sub-base aggregates category E sample was taken having dry…

A: Abrasion value is given by: AV=W2W1×100 Where, W2 = Weight of aggregate passing 1.7 mm sieve W1 =…

Q: 5.8 A sample of wet aggregate weighed 297.2 N. After drying in an oven, this sample weighed 281.5 N.…

A:

Q: bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained:…

A: V=0.3 ft3

Q: Calculate the percent voids between aggregate particles that have been compacted by rodding, if the…

A: Given that, Dry rodded unit weight of aggregate :  γb=1161 kg/m3 ⇒72.5 lb/ft3 Bulk dry specific…

Q: The sieve analysis results of an aggregate sample are provided below. What are the maximum…

A: Sieve size (mm)Mass retained (gms)9.504.7530.22.3675.41.18100.50.61350.31730.15121.90.07554Pan10To…

Q: 2. Three samples of aggregates are sieved to obtain the grading curve. A set of different sieves is…

A: Three samples of aggregates are given:-Sieve sizeMass of sieve (g)Mass of sieve+aggregates…

Q: Calculate the percent voids between aggregate particles that have been com-pacted by rodding, if the…

A: Given:  Dry unit weight yd = 1161 kg/m3 Specific gravity G = 2.639 To find: Percentage voids e = ?…

Q: Calculate the percent voids between aggregate particles that have been com- pacted by rodding, if…

A:

Q: Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit…

A: Given that,   The volume of rigid bucket= 0.2 ft3      Weight of empty bucket= 18.2 lb  Weight of…

Q: A results of sieve analysis test for sample of Aggregate are shown in below Table: Sieve Size Wt…

A: Since we only answer up to 3 sub-parts, we’ll answer the first three. Please resubmit the question…

Q: A sample of coarse aggregate is placed in a bucket of know volume (0.5 ft^3) and rodded with a…

A: Volume of bucket = 0.5 ft3Empty weight of the bucket = 20.3 lb

Q: Please solve points 4 and 5 only

A: Detailed solution is provided belowPlease read carefullyAsk me if you have any doubtsThank…

Q: Table shows the grain size distributions of aggregates A, and B. Answer the following questions and…

A: Given: The grain size distributions of aggregates are shown below,

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