Calorimeter mass 162.2 g Mass of calorimeter + cold water 226.6 g Initial temperature of cold water 22°C Temperature of hot water before mixing 85°C Final temperature of the mixture 46°C Mass of calorimeter + mixture 302.7 g Specific heat of water = 1cal/ g °C 10- ∆T H2O = ( Tm - T H2O cold) = ______________________________________ 11- ∆T H2O = ( Tm - T H2O hot) =___________________________________ 12- ∆T ° C = ∆T cold H2O:_________________________________________________ 13- Mass of cold water: = ( calorimeter mass + cold H2O - empty calorimeter mass):____ 14- Mass of hot water = ( mass of calorimeter + mixture) - ( mass of calorimeter + cold water) =.
Thermochemistry
Thermochemistry can be considered as a branch of thermodynamics that deals with the connections between warmth, work, and various types of energy, formed because of different synthetic and actual cycles. Thermochemistry describes the energy changes that occur as a result of reactions or chemical changes in a substance.
Exergonic Reaction
The term exergonic is derived from the Greek word in which ‘ergon’ means work and exergonic means ‘work outside’. Exergonic reactions releases work energy. Exergonic reactions are different from exothermic reactions, the one that releases only heat energy during the course of the reaction. So, exothermic reaction is one type of exergonic reaction. Exergonic reaction releases work energy in different forms like heat, light or sound. For example, a glow stick releases light making that an exergonic reaction and not an exothermic reaction since no heat is released. Even endothermic reactions at very high temperature are exergonic.
| Calorimeter mass | 162.2 g |
| Mass of calorimeter + cold water | 226.6 g |
| Initial temperature of cold water | 22°C |
| Temperature of hot water before mixing | 85°C |
| Final temperature of the mixture | 46°C |
| Mass of calorimeter + mixture | 302.7 g |
Specific heat of water = 1cal/ g °C
10- ∆T H2O = ( Tm - T H2O cold) = ______________________________________
11- ∆T H2O = ( Tm - T H2O hot) =___________________________________
12- ∆T ° C = ∆T cold H2O:_________________________________________________
13- Mass of cold water: = ( calorimeter mass + cold H2O - empty calorimeter mass):____
14- Mass of hot water = ( mass of calorimeter + mixture) - ( mass of calorimeter + cold water) =.
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