1:13 0* ll 66%iCyra GarcesActive NowCALORIMETRYHEAT OF FUSIONTrial 1Trial 2Mass of ice M (grams)7979Mass of warm waterMter (grams)120119Initial temperature of waterTinitial ("C)4142Final temperature of mixtureTfinal ("C)-4Calculated heat of fusion of iceLeperinemtal (cal/g)72.460.8Standard value of heat offusion of ice Lemdard(cal/g)79.779.7Percentage error9.22%23.76%CalculationsAccording to the principle of the conservation of energy, the quantity of heat absorbed by the ice asit melts (Quained melring) and then heats up to the final equilibrium temperature (Qpain by meltedice) must equal the quantity of heat released by the warm water (Qlast by warm water) as it cools downto the final equilibrium temperature.Mathematically:leguined metingl iast by warm waterpained meltingl + ocat(M(L) + (M)(1)T - OC) = (Mt(1)(Tie- Tfina- 0C) - (Mt(1finalwaterinitialMoreEditII- 1. For substances that will be in thermalcontact, how would we know which willabsorb energy (heat), and which willrelease energy in the form of heat?

Thermal equilibrium in thermodynamics is a state in which two or more substances in physical contact…

Answered: For substances that will be in thermal…

For substances that will be in thermal contact, how would we know which will absorb energy (heat), and which will release energy in the form of heat?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

1:13 0
* ll 66%i
Cyra Garces
Active Now
CALORIMETRY
HEAT OF FUSION
Trial 1
Trial 2
Mass of ice M (grams)
79
79
Mass of warm water
Mter (grams)
120
119
Initial temperature of water
Tinitial ("C)
41
42
Final temperature of mixture
Tfinal ("C)
-4
Calculated heat of fusion of ice
Leperinemtal (cal/g)
72.4
60.8
Standard value of heat of
fusion of ice Lemdard
(cal/g)
79.7
79.7
Percentage error
9.22%
23.76%
Calculations
According to the principle of the conservation of energy, the quantity of heat absorbed by the ice as
it melts (Quained melring) and then heats up to the final equilibrium temperature (Qpain by melted
ice) must equal the quantity of heat released by the warm water (Qlast by warm water) as it cools down
to the final equilibrium temperature.
Mathematically:
le
guined metingl iast by warm water
pained meltingl + o
cat
(M(L) + (M)(1)T - OC) = (Mt(1)(Tie- T
fina
- 0C) - (Mt(1
final
water
initial
More
Edit
II
-

1. For substances that will be in thermal
contact, how would we know which will
absorb energy (heat), and which will
release energy in the form of heat?

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