Find the Maclaurin series of the function. f(x) = In (1 – 6x) - Choose the Maclaurin series. 6"x" In (1 – 6x) = - 6"x" In (1 – 6x) = – E 6n n=1 (-1)"-16"x" In (1 - бх) - n= (-1)"-lx6n In (1 – 6x) = > 6n n=1 Identify the interval on which the series is valid. (Give your answer as an interval in the form (*, *). Use the symbol oo for infinity, u for combining intervals, and an appropriate type of parenthesis "(",")", "[","]" depending on whether the interval is open or closed. Enter Ø if the interval is empty. Express numbers in exact form. Use symbolic notation and fractions where needed.) The expansion is valid for: 6, ' 6 Incorrect Question Source: Rogawski 4e Calculus Eary T

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