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Given the following general solution 00 E (R + 1) + 3 A * (R-2) A = 0 R = 1 Set the coefficient portion of the power series equal to 0 and then solve for " AR +1". A ^(R+1) = (3R – 6) a, R ® A (R + 1) = R - 2 + 3A, 3 AR OA (R+1) %3D R - 2 -3 A, R. A (R + 1) R- 2 EA (R + 1) = AR + R R - 2 PA (R+1) 3 AR

Given the following general solution 00 E (R + 1) + 3 A * (R-2) A = 0 R = 1 Set the coefficient portion of the power series equal to 0 and then solve for " AR +1". A ^(R+1) = (3R – 6) a, R ® A (R + 1) = R - 2 + 3A, 3 AR OA (R+1) %3D R - 2 -3 A, R. A (R + 1) R- 2 EA (R + 1) = AR + R R - 2 PA (R+1) 3 AR

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Given the following general solution E (R - 2) A (R + 1) + 3 A = 0 R R = 1 Set the coefficient portion of the power series equal to 0 and then solve for " AR +1". O A (R + 1) = (3R – 6) A, - B A = R - 2 + 3A, (R+ 1) 3 AR (c A (R + 1) R - 2 - 3A, R (D) A (R + 1) R - 2 A (R + 1) = A. + R R R - 2 (F A (R + 1) 3 AR
Transcribed Image Text:Given the following general solution E (R - 2) A (R + 1) + 3 A = 0 R R = 1 Set the coefficient portion of the power series equal to 0 and then solve for " AR +1". O A (R + 1) = (3R – 6) A, - B A = R - 2 + 3A, (R+ 1) 3 AR (c A (R + 1) R - 2 - 3A, R (D) A (R + 1) R - 2 A (R + 1) = A. + R R R - 2 (F A (R + 1) 3 AR
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