Use substitution to find the Taylor series at x=0 of the function e -9x. Choose the correct Taylor series. 00 O A. E (- 1)"-1(9x)" 9²x g³x³ - = -1+9x - 2! n! -... n=0 3! 00 (9x) =1+9x + n! n = 0 9?x? 9³x³ О в. 2 2! +• .. 3! 00 (-9)-1x 9x? 92x3 +X- 9. 1 Oc. E %3D n! .... n=0 2! 3! 00 O D. E (-9x) 9x2 9³x3 =1-9x + 2! n! + ... n=0 3!
Use substitution to find the Taylor series at x=0 of the function e -9x. Choose the correct Taylor series. 00 O A. E (- 1)"-1(9x)" 9²x g³x³ - = -1+9x - 2! n! -... n=0 3! 00 (9x) =1+9x + n! n = 0 9?x? 9³x³ О в. 2 2! +• .. 3! 00 (-9)-1x 9x? 92x3 +X- 9. 1 Oc. E %3D n! .... n=0 2! 3! 00 O D. E (-9x) 9x2 9³x3 =1-9x + 2! n! + ... n=0 3!
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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
Transcribed Image Text:Use substitution to find the Taylor series at x = 0 of the function e -9x
Choose the correct Taylor series.
00
(-1)-1(9x)"
9²x² g³x³
Ο Α. Σ
= -1+9x -
2!
n!
- ...
n =0
3!
(9x)"
= 1+9x +
n!
О в. 2
9?x?
9°x
+
+ . ..
2!
3!
n =0
00
(-9)-1x
9x2 92x3
+X
1
Oc. E
%3D
n!
+
2!
....
n=0
3!
00
O D. E
(-9x)"
92x? 9x3
=1-9x+
2!
n!
+...
n = 0
3!
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