Find the Maclaurin series of the function. f(x) = In (1 – 6x) Choose the Maclaurin series. 6"x" In (1 – 6x) = Σ in 6"x" In (1 – 6x) = - %3D 6n n=1 (-1)"-'6"x" In (1 - 6х) n=1 00 (-1)"-1x6n ン6n In (1 – 6x) = n=1 Identify the interval on which the series is valid. (Give your answer as an interval in the form (*, *). Use the symbol ∞ for infinity, U for combining intervals, and an appropriate type of parenthesis "(",")", "[","]" depending on whether the interval is open or closed. Enter Ø if the interval is empty. Express numbers in exact form. Use symbolic notation and fractions where needed.) The expansion is valid for: Incorrect

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