Find the Maclaurin series of the function. f(x) = In (1 – 6x) Choose the Maclaurin series. In (1 – 6x) = (-1)"-lx6n 6n 00 n=1 00 6" x" In (1 – 6x) = Σ 6n n=1 In (1 – 6x) = (-1)"-'6"x" n=1 6" x" In (1 — 6х) : n=1 Identify the interval on which the series is valid. (Give your answer as an interval in the form (*, *). Use the symbol o for infinity, U for combining intervals, and an appropriate type of parenthesis "(",")", "L","]" depending on whether the interval is open or closed. Enter Ø if the interval is empty. Express numbers in exact form. Use symbolic notation and fractions where needed.) The expansion is valid for:

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